A plastic bag is massed. It is then filled with a gas which is insoluble in water and massed again. The apparent weight of the g

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A plastic bag is massed. It is then filled with a gas which is insoluble in water and massed again. The apparent weight of the g

as is the difference between these two masses. The gas is squeezed out of the bag to determine its volume by the displacement of water. What is the actual weight of the gas

Physics

1 answer:

levacccp [35] · Answer 1 · 2023-03-11T14:15:22+03:00

The actual weight of the gas = apparent weight + weight.

The actual weight = $W_{A}$ + W

Given that a plastic bag is massed. It is then filled with a gas which is insoluble in water and massed again.

If the apparent weight of the gas is the difference between these two masses, then let the apparent weight = $W_{A}$

The gas is squeezed out of the bag to determine its volume by the displacement of water. Since

density = mass / volume

The density of water is 1000 kg/ $m^{2}$

we can get the mass of the gas by making m the subject of the formula.

W = mg

The actual weight of the gas = apparent weight + weight

That is,

The actual weight = $W_{A}$ + W

Learn more about density here: brainly.com/question/406690