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Alexxandr [17]
2 years ago
7

A plastic bag is massed. It is then filled with a gas which is insoluble in water and massed again. The apparent weight of the g

as is the difference between these two masses. The gas is squeezed out of the bag to determine its volume by the displacement of water. What is the actual weight of the gas
Physics
1 answer:
levacccp [35]2 years ago
8 0

The actual weight of the gas = apparent weight + weight.

The actual weight = W_{A} + W

Given that a plastic bag is massed. It is then filled with a gas which is insoluble in water and massed again.

If the apparent weight of the gas is the difference between these two masses, then let the apparent weight = W_{A}

The gas is squeezed out of the bag to determine its volume by the displacement of water. Since

density = mass / volume

The density of water is 1000 kg/m^{2}

we can get the mass of the gas by making m the subject of the formula.

W = mg

The actual weight of the gas = apparent weight + weight

That is,

The actual weight =  W_{A} + W

Learn more about density here: brainly.com/question/406690

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WINSTONCH [101]

1) velocity: 98 m/s downward

Explanation:

The marble moves by uniformly accelerated motion, with constant acceleration a=g=-9.8 m/s^2 directed towards the ground. Therefore, its velocity at time t is given by:

v(t)=v_0 +at

where

v_0 = 0 is the initial velocity

a=g=-9.8 m/s^2 is the acceleration

t is the time

Substituting t = 10 s, we find:

v(10 s)=0+(-9.8 m/s^2)(10 s)=-98 m/s

And the negative sign means the direction of the velocity is downward.


2) Distance covered: 490 m

The distance covered in an uniformly accelerated motion can be found with the formula:

S=\frac{1}{2}at^2

where

a=-9.8 m/s^2 is the acceleration

t is the time

Substituting t=10 s, we find

S=\frac{1}{2}at^2=\frac{1}{2}(-9.8 m/s^2)(10 s)^2=-490 m

And the negative sign means the displacement is below the dropping point.

4 0
3 years ago
Why are mud shoes better then high heels
Ksju [112]

Answer:

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Explanation:

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3 years ago
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Let’s come back to the equation of SPEED OF AN ECHO
SPEED =2XDISTANCE/ TIME
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Hope you will get it right
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The function of a microscope is most similar to the function of a.............​
Nataly [62]

Answer:

Magnifying glass and a Petri dish.

Explanation:

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A student put her ear on one end of a long piece of lead. She asked her friend to
Ludmilka [50]

1) The length of the lead is 1700 m

2) The frequency of the wave is 400 Hz

Explanation:

1)

The wave in this problem is a sound wave, which is produced by the vibrations of the particles of air. It is a type of longitudinal wave (which means that the vibrations occur back-and-forth along the direction of propagation of the wave).

The speed of a sound wave in air is approximately

v = 340 m/s

In this problem, the sound wave is heard after a time of

t = 5 s

after the shot. Therefore, the distance travelled by the wave in this time (and therefore, the length of the lead) is

d=vt=(340)(5)=1700 m

2)

The frequency of a wave is the number of complete cycles made by the wave in one second.

For the wave in this problem, we are told that the wave has 2000 whole wavelengths in 5 seconds: this means that the wave completes 2000 cycles in 5 seconds. Therefore, we can find the frequency by setting up the following proportion:

\frac{2000}{5}=\frac{x}{1}

where x is the number of cycles made in 1 second. Solving for x,

x=\frac{2000\cdot 1}{5}=400 s^{-1}

Therefore, the frequency of the wave is

f=400 Hz

Learn more about waves and frequency:

brainly.com/question/5354733

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#LearnwithBrainly

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