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Alexxandr [17]
2 years ago
7

A plastic bag is massed. It is then filled with a gas which is insoluble in water and massed again. The apparent weight of the g

as is the difference between these two masses. The gas is squeezed out of the bag to determine its volume by the displacement of water. What is the actual weight of the gas
Physics
1 answer:
levacccp [35]2 years ago
8 0

The actual weight of the gas = apparent weight + weight.

The actual weight = W_{A} + W

Given that a plastic bag is massed. It is then filled with a gas which is insoluble in water and massed again.

If the apparent weight of the gas is the difference between these two masses, then let the apparent weight = W_{A}

The gas is squeezed out of the bag to determine its volume by the displacement of water. Since

density = mass / volume

The density of water is 1000 kg/m^{2}

we can get the mass of the gas by making m the subject of the formula.

W = mg

The actual weight of the gas = apparent weight + weight

That is,

The actual weight =  W_{A} + W

Learn more about density here: brainly.com/question/406690

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A 73.9 kg weight-watcher wishes to climb a
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The height to which the weight-watcher must climb to work off the equivalent 991 (food) Calories is 0.59 Km

<h3>How to determine the energy. </h3>

1 food calorie = 103 calories

Therefore,

991 food calories = 991 × 103

991 food calories = 102073 calories

Multiply by 4.2 to express in joule (J)

991 food calories = 102073 × 4.2

991 food calories = 428706.6 J

<h3>How to determine the height </h3>
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  • Mass (m) = 73.9 kg
  • Acceleration due to gravity (g) = 9.8 m/s²
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E = mgh

Divide both side by mg

h = E / mg

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h = 591.95 m

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h = 591.95 / 1000

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2 years ago
If an electron is accelerated from rest through a potential difference of 9.9 kV, what is its resulting speed
beks73 [17]

Answer:

v = 5.9 x 10⁷ m/s

Explanation:

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V = Potential Difference = 9.9 KV = 9900 Volts

The kinetic energy in general is given as:

K.E = \frac{1}{2}mv^{2}\\--------- equation (2)

where,

m = mass of electron = 9.1 x 10⁻³¹ kg

v = speed of electron = ?

Therefore, comparing equation (1) and equation (2), we get:

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<u>v = 5.9 x 10⁷ m/s</u>

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