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3 years ago

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The uniform 100-kg I-beam is supported initially by its end rollers on the horizontal surface at A and B. by means of the cable

at C, it is desired to elevate end B to a position 3 m above end A. Determine the required tension P, the reaction at A, and the angle q made by the beam with the horizontal in the elevated position.

1 answer:

Ann [662]3 years ago

8 0

I attached a free body diagram for a better understanding of this problem.

We start making summation of Moments in A,

$\sum M_A = 0$

$P(6cos\theta)-981(4cos\theta)=0$

$P=654N$

Then we make a summation of Forces in Y,

$\sum F_y = 0$

$654+R-981 = 0$

$R=327N$

At the end we calculate the angle with the sin.

$sin\theta = \frac{3m}{4m+2m+2m} = \frac{3m}{8m}$

$\theta = 22.02\°$

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From the question we are told that

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3 years ago

A soccer player kicks a rock horizontally off a 37 m high cliff into a pool of water. If the player hears the sound of the splas

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<h2>Answer:</h2>

<em><u>(a). 16.741 m/s</u></em>

<em><u>(b). 15.75 m/s</u></em>

<h2>Explanation:</h2>

In the question,

Height of the cliff, h = 37 m

Time taken to reach the sound to us = 2.92 s

Speed of the sound in air at room temperature = 343 m/s

Now,

Let us say the speed of the ball = u m/s

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t = 2.92 - 2.747

t = 0.172 s

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$Distance=Speed\times Time\\45.99=u\times 2.747\\u=16.741\,m/s$

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(b).

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<u>Distance traveled by sound</u> is,

$Distance=331\times 0.172\\Distance=56.932\,m$

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Distance traveled in the horizontal by ball is,

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So,

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Explanation:

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Answer:

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