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2 years ago

Express 400cm as a decimal of 4km

Mathematics

1 answer:

postnew [5]2 years ago

6 0

400cm = 0.004km.

Perhaps there is something else your question meant, but it is way to unspecific.

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Find the length of the curve y = 3/5x^5/3 - 3/4x^1/3 + 6 for 1 < = x < = 8. The length of the curve is . (Type an exact an

Mashutka [201]

Answer:

$\sqrt\frac{387}{20}$

Step-by-step explanation:

$Arc Length =\int\limits^a_b {\sqrt{1+(\frac{dy}{dx})^2 } } \, dx$

$y=\dfrac{3}{5}x^{\frac{5}{3}}- \dfrac{3}{4}x^{\frac{1}{3}}+6$

$\frac{dy}{dx} =x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}}$

$1+(\frac{dy}{dx})^2 }=1+(x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}})^2\\=1+(x^{\frac{4}{3}}-\dfrac{1}{2}+ \dfrac{1}{16}x^{-\frac{4}{3}})$

$=\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}}$

For the Interval $1\leq x\leq 8$

Length of the Curve $=\int\limits^8_1 {\sqrt{\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}} } } \, dx\\$

Using T1-Calculator

$=\sqrt\frac{387}{20}$

3 0

3 years ago

How many triangles can be made if one angle is 95° and another angle is obtuse?

Elenna [48]

D. None. Say the obtuse angle is 100 degrees. Since the sum of all angles in a triangle cannot be bigger than 180, it's not possible because 195 (100+95) is greater than 180 degrees. Hope this helps.

4 0

3 years ago

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Suppose a spider was able to create one thread that would extend from the top-right back corner of a room to the bottom-left fro

NNADVOKAT [17]

Answer:

d^2 = 30^2 + 12^2

e^2 = d^2 + 8^2

e^2 = 30^2 + 12^2 + 8^2

e = √(30^2 + 12^2 + 8^2) = 33.3 ft

7 0

3 years ago

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What is the relationship between the sine and cosine of complementary angles?

pochemuha

<span> Yes, there is a "relationship" regarding the </span>tangent<span> of the two acute angles (A and B) in a right triangle.</span>

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3 years ago

Is the ordered pair a solution of y ≥ 2x − 5? a. (3, 1) b. (1, −4)

Deffense [45]

Answer:

a. Yes

b. No

Step-by-step explanation:

To find if an ordered pair is a solution to the inequality, substitute its x and y values for the x and y in the inequality and solve. If the equation is true, then it is a solution. If it is not, then it is not a solution.

1) First, substitute the x and y values of (3, 1) into the inequality. So, substitute 3 for x and 1 for y:

$1 \geq 2(3)-5\\1\geq 6-5\\1\geq 1$

1 is greater than or equal to 1, so (3,1) is a solution.

2) Second, do the same with the point (1, -4). Substitute 1 for x and -4 for y:

$-4\geq 2(1)-5\\\\-4\geq 2-5\\-4\geq -3$

However, -4 is not greater than or equal to -3, thus (1, -4) is not a solution.

4 0

3 years ago