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Sauron [17]
3 years ago
12

I need your help please :( any body if u know can I get a answer

Chemistry
1 answer:
ycow [4]3 years ago
5 0

Answer:

have you use you brainly questions up or is it not a answered question?

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The average strength of a hydrogen bond is approximately what percent of the average strength of a covalent bond?
lozanna [386]

<span>Hydrogen bonds are approximately 5% of the bond strength of covalent bonds, for example (C-C or C-H bonds).
Hydrogen bonds strength in water is approximately 20 kJ/mol, strenght of carbon-carbon bond is approximately 350 kJ/mol and strengh of carbon-hydrogen bond is approximately 340 kJ/mol.
20 kJ/350 kJ = 0,057 = 5,7 %.</span>

8 0
3 years ago
When a person looks at a bright light, tiny muscles in the eye contract so less light can enter the eye.
bagirrra123 [75]

Answer:

involuntary, attached to the eyeball, nonstriated.

Explanation:

6 0
3 years ago
Read 2 more answers
When writing a formula for a compound having a transition metal in it, _____.
Stella [2.4K]

Answer:

it is always necessary to use the roman numeral as the assigned charge of the metal.

Explanation:

This is so that one would know which Transition metal is being used. For example copper (II) would be Cu²+

3 0
3 years ago
If the take off velocity of an airplane on a runway is 300 km /hr with an acceleration of 1 m/s2. What is the take off time of t
Rama09 [41]
<h3>Answer:</h3>

83.33 seconds.

<h3>Explanation:</h3>

<u>We are given;</u>

  • Take off velocity as 300 km/hr
  • Acceleration as 1 m/s²

We are required to calculate the take off time of the airplane.

<h3>Step 1: Convert velocity from km/hr to m/s </h3>

We are going to use the conversion factor.

The conversion factor is 3.6 km/hr per m/s

Therefore;

Velocity = 300 km/hr ÷ 3.6 km/hr per m/s

             = 83.33 m/s

<h3>Step 2: Calculate the take off time</h3>

We know that;

v = u + at

where, u is the initial velocity, v the final velocity, a the acceleration and t is time.

But, initial velocity is Zero

Therefore;

83.33 m/s = 1 m/s² × t

Thus;

time = 83.33 m/s ÷ 1 m/s²

       = 83.33 seconds

Therefore, the take off time is 83.33 seconds.

5 0
3 years ago
The proper name for PCl6 is phosphorus hexachloride.<br><br> TRUE<br><br> FALSE
Alenkasestr [34]
The proper name for PCI6 is phosphorus hexachloride. Therefore it’s true
8 0
3 years ago
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