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den301095 [7]
2 years ago
12

Consider 5.00 L of a gas at 365 mmHg and 20. ∘C . If the container is compressed to 2.50 L and the temperature is increased to 3

1 ∘C , what is the new pressure, P2, inside the container? Assume no change in the amount of gas inside the cylinder.
Chemistry
1 answer:
pickupchik [31]2 years ago
4 0

First convert celcius to Kelvin.

20 + 273 = 293K

31 + 273 = 304K

Now we can set up an equation based on the information we have.

V1 = 5

P1 = 365

T1 = 293

V2 = 5

P1 = x

T2 = 304

The equation be:  \frac{(5)(365)}{293} = \frac{5x}{304}

Now just solve.

1825/293 = 5x/304

Cross multiply.

554800 = 1465x

Divide both sides by 1465

x = 378.7030717 which can then be rounded to 378.7 mmHg

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Answer:

3.38%

Explanation:

Given that;

the mass of the whole milk sample = 100 g

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molarity of HCl = 0.5 M

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molarity of NaOH = 0.3512 M

Since we knew the molarity and volume of both HCl and NaOH; we can calculate their corresponding number of moles present.

So, number of moles of HCl = molarity of HCl × volume of HCl

number of moles of HCl = 0.5 M ×  0.100 mL

                                        = 0.05 mole

number of moles of NaOH = Molarity of NaOH ×  Volume of NaOH

number of moles of NaOH = 0.3512 M ×  0.0345 L

                                            = 0.012 mole

From the question, we can deduce that the number of HCl that is consumed by NH₃ is equal to the number of moles of HCl that is consumed by NaOH.

SO, number of moles of HCl consumed by NH₃ = Total moles of HCl - moles of HCl consumed by NaOH

= 0.05 mole - 0.012 mole

= 0.038 mole

However, to determine the mole of NH₃ present , we have:

number of moles of NH₃ present = number of moles of HCl consumed by NH₃  = 0.038

∴ the mass of Nitrogen with the molecular weight (14.0 g/mol) = 0.038 moles × 14.0 g/mol

= 0.530 g

Now, the percentage of Nitrogen can be calculated as;

percentage of nitrogen =\frac{mass of nitrogen}{mass of the whole milk sample} *100

percentage of nitrogen =\frac{0.530g}{100g} *100

percentage of nitrogen =0.530%%

the percentage of protein in the sample = CP × %age of N

where CP is given as 6.38

∴ the percentage of protein in the sample = 6.38 ×  0.530%

the percentage of protein in the sample = 3.3814%

the percentage of protein in the sample = 3.38%

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Please see the step-by-step solution in the picture attached below.

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