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den301095 [7]
3 years ago
12

Consider 5.00 L of a gas at 365 mmHg and 20. ∘C . If the container is compressed to 2.50 L and the temperature is increased to 3

1 ∘C , what is the new pressure, P2, inside the container? Assume no change in the amount of gas inside the cylinder.
Chemistry
1 answer:
pickupchik [31]3 years ago
4 0

First convert celcius to Kelvin.

20 + 273 = 293K

31 + 273 = 304K

Now we can set up an equation based on the information we have.

V1 = 5

P1 = 365

T1 = 293

V2 = 5

P1 = x

T2 = 304

The equation be:  \frac{(5)(365)}{293} = \frac{5x}{304}

Now just solve.

1825/293 = 5x/304

Cross multiply.

554800 = 1465x

Divide both sides by 1465

x = 378.7030717 which can then be rounded to 378.7 mmHg

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2S(s) + 3O₂(g) → 2SO₃(g)  ΔH = -790 kJ

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2S(s) + 3O₂(g) + 2SO₂(g) → 2SO₃(g) + 2S(s) + 2O₂(g)

Simplifing the compounds that are in both sides (bolded):

2SO₂(g) + O₂(g) → 2SO₃(g) ΔH = -790 + 594 = -196 kJ

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