Question

A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 6.96 m/s. The car is a distance d away. The bear is 23.3 m behind the tourist and running at 10.3 m/s. The tourist reaches the car safely. What is the maximum possible value for d

Answer 1

The tourist reaches the car safely. The maximum possible value for d will be 44.6 m.

What is the distance?

Distance is a numerical representation of the distance between two objects or locations.

The distance can refer to a physical length or an estimate based on other factors in physics or common use. |AB| is a symbol for the distance between two points A and B.

When the bear just touches the tourist, let T be the time.

$\rm T= \frac{D}{v_1-v_2} \\\\ T=\frac{23.3}{10.3-6.96} \\\\ T=6.67 sec$

The tourist must arrive at the car inside this window in order to be safe.

d≤speed of tourist × time

d≤6.69 × 6.67

d≤44.6 m

Hence, the maximum possible value for d will be 44.6 m.

To learn more about the distance refer to the link;

brainly.com/question/26711747

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