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The magnitude of the force on the left-hand pole of the thin flexible gold chain of uniform linear density with a mass of 17.1 and, hangs between two 30.0 cm long vertical sticks, which are a distance of 30.0 cm apart will be, 0.167N.
To find the correct answer, we have to know more about the Basic forces that acts upon a body.
<h3>What is force and which are the basic forces that acts upon a body?</h3>- A push or a pull which changes or tends to change the state or rest, or motion of a body is called Force.
- Force is a polar vector as it has a point of application.
- Positive force represents repulsion and the negative force represented attraction.
- There are 3 main forces acting on a body, such as, weight mg, normal reaction N, and the Tension or pulling force.
- We have given that, the gold chain hangs between the vertical sticks of 30cm and the horizontal distance between then is 30cm.
- From the given data, we can find the angle (in the free body diagram, it is given as θ).
- From the free body diagram given, we can write the balanced equations of total force along y direction as,
- From the free body diagram given, we can write the balanced equations of total force along x direction as,
Thus, we can conclude that, the magnitude of force on the left-hand pole will be 0.167N.
Learn more about the Basic forces that acts upon a body here:
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