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galina1969 [7]
2 years ago
8

What is the simplest method of determining the composition of a compound?

Chemistry
1 answer:
kaheart [24]2 years ago
8 0

Answer:

Chemical formulas tell you how many atoms of each element are in a compound, and <u>empirical formulas</u> tell you the simplest or most reduced ratio of elements in a compound. If a compound's chemical formula cannot be reduced anymore, then the empirical formula is the same as the chemical formula.

please give me brainliest

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GIVEN BRAINLIEST
umka21 [38]

Answer:

A. your observations in writing

Explanation:

Descriptive investigation is one of the mode of inquiries in science. It is devoid of the usual collection of data in the field or setting up laboratory experiments to compared variables.

  • In descriptive investigation, observations are usually done in writing.
  • They are usually common in Astrology.
  • Such investigation involves a question without a hypothesis ensuing.
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6 0
4 years ago
65. Write an equation for the combustion of octane.
siniylev [52]

Answer:

2C8H18+25O2→16CO2+18H2O.



4 0
3 years ago
The new boiling point is 101.02°C. Suppose that you add another 2.0 mol of sucrose to this solution. What do you predict the new
solniwko [45]

Mad Lad, thanks for the answer :)

7 0
3 years ago
Read 2 more answers
Answer True or False for each of the following statements. (a) The carburization surface was maintained at slightly less than 0.
fomenos

Answer:

verdadero/a

falso/b

verdadero/c

Explanation:

6 0
3 years ago
What is the limiting reagent when a 2.00 g sample of ammonia is mixed with 4.00 g of oxygen?​
UNO [17]

Answer:

Ammonia is limiting reactant

Amount of oxygen left  = 0.035 mol

Explanation:

Masa of ammonia = 2.00 g

Mass of oxygen = 4.00 g

Which is limiting reactant = ?

Balance chemical equation:

4NH₃ + 3O₂     →     2N₂ + 6H₂O

Number of moles of ammonia:

Number of moles = mass/molar mass

Number of moles = 2.00 g/ 17 g/mol

Number of moles = 0.12 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 4.00 g/ 32 g/mol

Number of moles = 0.125 mol

Now we will compare the moles of ammonia and oxygen with water and nitrogen.

                      NH₃          :            N₂

                        4             :             2

                      0.12           :           2/4×0.12 = 0.06

                      NH₃         :            H₂O

                        4            :             6

                        0.12       :           6/4×0.12 = 0.18

                       

                       O₂            :            N₂

                        3             :             2

                      0.125        :           2/3×0.125 = 0.08

                        O₂           :            H₂O

                        3              :             6

                        0.125       :           6/3×0.125 = 0.25

The number of moles of water and nitrogen formed by ammonia are less thus ammonia will be limiting reactant.

Amount of oxygen left:

                        NH₃          :             O₂

                           4            :              3

                           0.12       :          3/4×0.12= 0.09

Amount of oxygen react = 0.09 mol

Amount of oxygen left  = 0.125 - 0.09 = 0.035 mol

3 0
3 years ago
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