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3 years ago

_Cuo +H, → _Cu + _H,0

Chemistry

1 answer:

Elena-2011 [213]3 years ago

3 0

<h3>Answer:</h3>

CuO(s) + H₂(g) → Cu(s) + H₂O(l)

<h3>Explanation:</h3>

Assuming the reaction is the reduction of CuO by H₂
Then the balanced equation for the reaction is;

CuO(s) + H₂(g) → Cu(s) + H₂O(l)

The equation shows the reducing property of hydrogen gas, such that hydrogen reduces metal oxides such as copper(ii)oxide to the respective metals.
The law of conservation requires chemical equations to be balanced so as the mass of reactants will be equal to that of products.

In this case; there is 1 copper atom, 1 oxygen atom and 2 hydrogen atoms on both side of the equation and thus the equation is balanced.

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Answer:

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$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

$=\frac{m}{T}\times 100=\frac{5.76 g}{11.988 g}\times 100=48.05\%$

The percent yield of a reaction is 48.05%.

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