Question

Lucite contains 59.9 g C, 8.06 g H,

Answer 1

You start by finding the mol of each

59.9g C x (mol C / 12.01 g C) = 4.98 mol C
8.06g H x (mol H / 1.00 g H) = 8.06 mol H
32.0 g O x (mol O / 16.0 g O) = 2 mol O

So when you set it up you have
C4.98 H8 O2

You divide each by the smallest mol. The smallest mol is 2

C2 H4 O2.5

However you can’t have half a mol in the empirical formula. If the value ends in 0.5, you multiply everything by 2

You’re left with

C2H8O5

The EMPIRICAL formula for lucite is C2H8O5

Note empirical is not the same as chemical formula.