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hram777 [196]
3 years ago
11

An element has two naturally-occurring isotopes. The mass numbers of these isotopes are 113 amu and 115 amu, with natural abunda

nces of 5% and 95%, respectively. Calculate its average atomic mass. Report your answer to 1 decimal place.
Chemistry
1 answer:
DENIUS [597]3 years ago
5 0

Answer: Its average atomic mass is 114.9 amu

Explanation:

Mass of isotope 1 = 113 amu

% abundance of isotope 1 = 5% = \frac{5}{100}=0.05

Mass of isotope 2 = 115 amu

% abundance of isotope 2 = 95% = \frac{95}{100}=0.95

Formula used for average atomic mass of an element :

\text{ Average atomic mass of an element}=\sum(\text{atomic mass of an isotopes}\times {{\text { fractional abundance}})

A=\sum[(113\times 0.05)+(115\times 0.95)]

A=114.9amu

Thus its average atomic mass is 114.9 amu

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Explanation:

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Key terms: Reset Compounds that contain a carbon-carbon double bond are known as ____________ . Alkenes are electron rich; there
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Answer: Compounds that contain a carbon-carbon double bond are known as _____alkenes_______ . Alkenes are electron rich; therefore, simple alkenes do not react with _____nuceophiles_______ or bases, but will react with _____electrophiles_______ or acids. In the IUPAC system, an alkene is identified by the suffix _____-ene_______ . Addition reactions in which two parts of a reagent are added to the same side of a double bond are known as _____syn_______ additions. Addition reactions in which two parts of a reagent are added from opposite sides of a double bond are called _____anti_______ additions. Halogenation and halohydrin formation occur with _____anti_______ addition. Hydroboration occurs with _____syn_______ addition.

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There are two binary compounds of mercury and oxygen. heating either of them results in the decomposition of the compound, with
grandymaker [24]

\text{Hg} \text{O} and \text{Hg}_{2} \text{O}.

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n(\text{Hg}) : n(\text{O}) \approx  2:1 and therefore the empirical formula

\text{Hg}_{2} \text{O}.

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