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ExtremeBDS [4]
3 years ago
8

A diamond’s density is 3.2 g/cm3. Determine the volume of a diamond that has a mass of 1 g.

Chemistry
2 answers:
Nutka1998 [239]3 years ago
8 0
The volume is 0.3125 cubic meter I did it on calculator
svetlana [45]3 years ago
5 0

Answer:

https://socratic.org/questions/diamond-has-a-density-of-3-52-g-ml-what-is-the-volume-in-cubic-centimeters-of-a-

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True or false?<br><br> When sodium and chlorine combine and bond, a molecule is formed.
CaHeK987 [17]

When Sodium and Chlorine come together they transfer an electron.

- Source: google


Hopefully this was clear and you understood!

3 0
3 years ago
PLZZZZ HELP!!!!!! WILL GIVE BRAINLIEST!!
guapka [62]
Color change bubbles and i think dissolving
4 0
3 years ago
Read 2 more answers
Hund's rule states that electrons must spread out within a given subshell before they can pair
Temka [501]

Answer:

Groups 14, 15, and 16 have 2,3, and 4 electrons in the p sublevel (p sublevel has 3 "spaces" AKA orbitals), because Hunds says one in each orbital before doubling up if you had 2 electrons, group 14, they would both be in the first orbital, with 3 electrons, group 15, two in the first orbital one in the 2nd none in the 3rd. With 4 electrons, group 16, then you would have 2 in the first 2 orbitals and NONE in the 3rd.

Explanation:

If you are in group 13 you only have 1 electron so it can only be in one orbital. with group 17, you have 5 electrons, so 2 in the first 2 in the second and 1 in the 3rd, correct for Hunds rule anyway. Noble gasses, group 18, have 6 elecctrons, so every orbital is full any way you look at it.

6 0
2 years ago
Use the following information to answer the following question.
Irina-Kira [14]

Answer:

For these problems, we need to compare the theoretical yield that we'd get from performing stoichiometry to the actual yield stated in the problem. % yield is the actual yield/theoretical yield x 100%  

Cu + 2 AgNO₠→ Cu(NOâ‚)â‚‚ + 2 Ag ==> each mole of copper yields two moles of silver  

12.7-g Cu x ( 1 mol Cu /63.5-g Cu) x ( 2 mol Ag / 1 mol Cu) x (108-g Ag / 1 mol Ag) = 43.2-g Ag. This is the theoretical yield. Now, since we got 38.1-g Ag our % yield is:  

38.1-g/43.2-g x 100% = 88.2%

Explanation:

5 0
2 years ago
HELP ASAP WILL MARK BRAINLIEST: How many grams of aluminum can be extracted from 5000g of alumina
Lesechka [4]

The grams of aluminium extracted from 5000g of alumina is 2647 grams

<h3>Chemical formula of alumina:</h3>
  • Al₂O₃

Let's calculate the molecular mass of Al₂O₃

Al₂O₃ = 27 × 2 + 16 × 3 = 54 + 48 = 102 g/mol

Therefore,

102 g of Al₂O₃ = 54 g of aluminium  

5000g of Al₂O₃  = ?

mass of aluminium produced = 5000 × 54 / 102

mass of aluminium produced = 270000 / 102

mass of aluminium produced  = 2647.05882353

mass of aluminium produced  = 2647 grams

learn more on mass here: brainly.com/question/14627327

4 0
2 years ago
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