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Alborosie
3 years ago
7

An unknown element, x, reacts with rubidium to form the compound rb2x. in other compounds this element also can accommodate up t

o 12 electrons rather than the usual octet. what element could x be?
Chemistry
1 answer:
SVETLANKA909090 [29]3 years ago
6 0

There are few elements that can form 12 electron rather than the usual 8. Therefore these are the possible answers:

Sulfur = 2Na + S --> Na2S <span>
Selenium = 2Na + Se --> Na2Se 
<span>Tellurium = 2Na + Te --> Na2Te</span></span>

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Hydrogen is special because it can act like two groups, _____<br> and _____
Vedmedyk [2.9K]

Answer: gas and alkaline earth metal

Explanation:

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A patient needs to take 625 mg of ibuprofen twice daily. The pills in the bottle are each 250. mg. How many pills does the patie
WINSTONCH [101]
2 and a half
250 x 2 =500
250/2=125
and 125 is a half of 250
so your answer is
2 and a half
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what is the suggested weight of the sample that should be disssolved in the beaker before it is transferred to the NMR tube
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3 0
2 years ago
A) 24 g<br> B) 36 g<br> C) 48 g<br> D) 60 g
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A. 24 g

5 0
3 years ago
If 2.0 g of copper(II) chloride react with excess sodium nitrate, what mass of sodium chloride is formed in this double replacem
cluponka [151]

Taking into account the reaction stoichiometry, 1.729 grams of NaCl is formed.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

CuCl₂ + 2 NaNO₃ → Cu(NO₃)₂ + 2 NaCl

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

  • CuCl₂: 1 mole
  • NaNO₃: 2 moles
  • Cu(NO₃)₂ : 1 mole
  • NaCl: 2 moles

The molar mass of the compounds is:

  • CuCl₂: 134.44 g/mole
  • NaNO₃: 85 g/mole
  • Cu(NO₃)₂ : 187.54 g/mole
  • NaCl: 58.45 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

  • CuCl₂: 1 mole ×134.44 g/mole= 134.44 grams
  • NaNO₃: 2 moles ×85 g/mole= 170 grams
  • Cu(NO₃)₂ : 1 mole ×187.54 g/mole= 187.54 grams
  • NaCl: 2 moles ×58.45 g/mole= 116.9 grams

<h3>Mass of NaCl formed</h3>

The following rule of three can be applied: If by stoichiometry of the reaction 134.44 grams of CuCl₂ form 116.9 grams of NaCl, 2 grams of CuCl₂ form how much mass of NaCl?

mass of NaCl=\frac{2 grams of CuCl_{2}x116.9 grams of NaCl }{134.44grams of CuCl_{2}}

<u><em>mass of NaCl= 1.739 grams</em></u>

Finally, 1.729 grams of NaCl is formed.

Learn more about the reaction stoichiometry:

brainly.com/question/24741074

brainly.com/question/24653699

6 0
2 years ago
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