Answer:
The limiting reactant is propane, C₃H₈ and the percentage yield is 83.77%
Explanation:
Mass of propane = 0.1240 kg = 124 g
Mass of carbon dioxide = 0.3110 kg = 311 g
Molar mass of propane = 44.1 g/mol
Molar mass of carbon dioxide = 44.01 g/mol
Number of moles of propane = 124/44.1 = 2.812 moles
Number of moles of carbon dioxide = 311/44.01 = 7.067 moles
Equation for the reaction
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
Hence 1 mole of propane ideally yields 3 moles of CO₂
Hence, 2.812 moles of propane will yield 3×2.812 moles = 8.44 moles of CO₂
Since, oxygen is in excess, therefore, the limiting reactant = Propane, C₃H₈
The percentage yield = 7.067/8.44× 100 = 83.77%.