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ArbitrLikvidat [17]
3 years ago
14

Why is graphite used instead of gold or copper wires to conduct electricity in very hot situations such as an industrial kiln?

Chemistry
2 answers:
Amanda [17]3 years ago
7 0

In very hot situations like an industrial klin, there is risk of melting of wires if they are made up of metal with low melting point. Also, metal with high electrical conductivity is required under such situations.

Graphite is good conductor of heat and electricity also, it has very high melting point therefore, it is used instead of copper and gold with low melting point to make wires.

Other advantages of graphite are it is thermal shock resistant, The coefficient of thermal expansion is 3 times less than that of copper. The melting of graphite does not take place and it gets converted directly from solid to liquid at 3400 °C (extremely high temperature). It forms lighter electrode because density of graphite is 5 times less than that of copper.

Molodets [167]3 years ago
4 0
It wont melt like gold and copper would at that temperature

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LiF or lithium fluoride is the non covalent molecule or ionic compound.

Option 3.

<h3><u>Explanation:</u></h3>

Covalent molecules are those molecules which do have actual bonds between the atoms present in the molecule by sharing of the electrons. But in ionic molecules, there's no actual bonds between the atoms, but the oppositely charged ions are attracted towards each other by means of electrostatic force of attraction.

The molecules that are formed by the atoms with high electronegativity and electropositivity are actually ionic because the atoms with high electronegativity are able to actually gain electron readily and the atoms with high electropositivity are actually ready to give the electrons to the electronegative elements.

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According to the dilution law, the degree of ionization increases on a dilution and it is inversely proportional to the square root of concentration. The degree of dissociation of an acid is directly proportional to the square root of a volume.

M₁V₁=M₂V₂

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Rearrange the formula for M₂

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Therefore, the concentration of a dextrose solution after the dilution is 0.56M.

To know more about dilution

brainly.com/question/18566203

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