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ArbitrLikvidat [17]
3 years ago
14

Why is graphite used instead of gold or copper wires to conduct electricity in very hot situations such as an industrial kiln?

Chemistry
2 answers:
Amanda [17]3 years ago
7 0

In very hot situations like an industrial klin, there is risk of melting of wires if they are made up of metal with low melting point. Also, metal with high electrical conductivity is required under such situations.

Graphite is good conductor of heat and electricity also, it has very high melting point therefore, it is used instead of copper and gold with low melting point to make wires.

Other advantages of graphite are it is thermal shock resistant, The coefficient of thermal expansion is 3 times less than that of copper. The melting of graphite does not take place and it gets converted directly from solid to liquid at 3400 °C (extremely high temperature). It forms lighter electrode because density of graphite is 5 times less than that of copper.

Molodets [167]3 years ago
4 0
It wont melt like gold and copper would at that temperature

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What volume of concentrated (10.2 M) HCl would be required to prepare 1.11 x 104 mL of 1.5 M HC1? Enter your answer in scientifi
Tomtit [17]

Answer:

The required volume is 1.6 x 10³mL.

Explanation:

When we want to prepare a dilute solution from a concentrated one, we can use the dilution rule to find out the required volume to dilute. This rule states:

C₁ . V₁ = C₂ . V₂

where,

C₁ and V₁ are the concentration and volume of the concentrated solution

C₂ and V₂ are the concentration and volume of the dilute solution

In this case, we want to find out V₁:

C₁ . V₁ = C₂ . V₂

V_{1} = \frac{C_{2}.V_{2}}{C_{1}} = \frac{1.5M \times1.11.10^{4}mL }{10.2M} =1.6\times10^{3} mL

3 0
3 years ago
How many joules of heat are required to heat 110 g of aluminum from 52.0 oC to 91.5 oC?
docker41 [41]

Answer:

We need 3910.5 joules of energy

Explanation:

Step 1: Data given

Mass of aluminium = 110 grams

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Final temperature = 91.5 °C

Specific heat of aluminium = 0.900 J/g°C

Step 2: Calculate energy required

Q = m*c*ΔT

⇒with Q = the energy required = TO BE DETERMINED

⇒with m = the mass of aluminium = 110 grams

⇒with c = the specific heat of aluminium = 0.900 J/g°C

⇒with ΔT = the change in temperature = T2 - T1 = 91.5 °C - 52.0 °C = 39.5 °C

Q = 110 grams * 0.900 J/g°C * 39.5

Q = 3910.5 J

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6 0
3 years ago
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egoroff_w [7]
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<span>E_Kr / E_Ne = sqrt ( M_Ne / M_Kr) 
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7 0
2 years ago
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Which example illustrates public scientific communication?
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Answer:

D. A federal government agency publishes an article in a professional scientific journal detailing technical details of a  new virus.

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8 0
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