Considering ideal gas behavior, the volume of 1 mol of gas at STP is 22.4 L; then the volume occupied by 1.9 moles is 1.9mol*22.4L/mol = 42. 6 L.
Answer: 43 L
Here's the procedure to Crack an egg ~
Step 1 ~
- Hold the egg in your hand and tap it on a firm surface
Step 2 ~
- Gently pull the shells apart
Step 3 ~
- And release the yolk in the bowl
The volume in liters occupied by 22.6 g of I₂ gas at STP is 1.99 L (answer A)
<u><em>calculation</em></u>
Step: find the moles of I₂
moles= mass÷ molar mass
from periodic table the molar mass of I₂ is 253.8 g/mol
moles = 22.6 g÷253.8 g/mol =0.089 moles
Step 2:find the volume of I₂ at STP
At STP 1 moles =22.4 L
0.089 moles= ? L
<em>by cross multiplication</em>
={ (0.089 moles x 22.4 L) /1 mole} = 1.99 L
Answer:
See the answer and explanation below , please.
Explanation:
A conjugate base is defined as that formed after an acid donates its proton.
For each article, a continuation of the conjugate bases (highlighted in bold), for dissociation in water:
a) HF + H20 --> F- + H30+
b) H20+ H20 --> OH- + H30+
C)H2PO3- + H20--> HPO3 2- + H30+
d) HSO4- + H20 --> SO4 2- + H30+
E) HCL02 + H20 --> CLO02 - + H30+
When equilibrium has been reached so, according to this formula we can get the specific heat of the unknown metal and from it, we can define the metal as each metal has its specific heat:
Mw*Cw*ΔTw = Mm*Cm*ΔTm
when
Mw → mass of water
Cw → specific heat of water
ΔTw → difference in temperature for water
Mm→ mass of metal
Cw→ specific heat of the metal
ΔTm → difference in temperature for metal
by substitution:
100g * 4.18 * (40-39.8) = 8.23 g * Cm * (50-40)
∴ Cm = 83.6 / 82.3 = 1.02 J/g.°C
when the Cm of the Magnesium ∴ the unknown metal is Mg
