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timurjin [86]
1 year ago
9

A4.00-kg box sits on a ramp that is inclined at 30°above the horizontal.The coefficient of kinetic friction between the box and

the ramp is uk=0.32.What horizontal force is required to move the box up the incline with a constant
acceleration of 3.0m/s2?
Physics
1 answer:
enot [183]1 year ago
3 0

From the calculation, we can see that the force that  moves the box forward is 5.7 N.

<h3>What is frictional force?</h3>

The term frictional force refers to the force that opposes motion. Given that;

ma = ukmgcosθ + F

Let F be the forward force.

Hence;

F = ma - ukmgcosθ

F = 4 * 3 - (0.32 * 4.00 * 9.8 * sin 30)

F =  5.7 N

Learn more about frictional force:brainly.com/question/14662717

#SPJ1

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