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Anarel [89]
3 years ago
5

Car 1 of mass m1 is waiting at a traffic light.

Physics
1 answer:
defon3 years ago
7 0

Answer: KE= 1/2 m v^2

KE= 1/2 2500 (0)^2

KE= 0

Explanation: since initial velocity is 0, the KE is 0.

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Suppose two children push horizontally, but in exactly opposite directions, on a third child in a wagon. The first child exerts
Nata [24]

(a) The system of interest if the acceleration of the child in the wagon is to be calculated are the wagon and the children outside the wagon.

(b) The acceleration of the child-wagon system is 0.33 m/s².

(c) Acceleration of the child-wagon system is zero when the frictional force is 21 N.

<h3>Net force on the third child</h3>

Apply Newton's second law of motion;

∑F = ma

where;

  • ∑F is net force
  • m is mass of the third child
  • a is acceleration of the third child

∑F = 96 N - 75 N - 12 N = 9 N

Thus, the system of interest if the acceleration of the child in the wagon is to be calculated are;

  • the wagon
  • the children outside the wagon

<h3>Free body diagram</h3>

           →                 →              Ф                         ←

         1st child      friction       wagon                2nd child

<h3>Acceleration of the  child and wagon system</h3>

a = ∑F/m

a = 9 N / 27 kg

a = 0.33 m/s²

<h3>When the frictional force is 21 N</h3>

∑F = 96 N - 75 N - 21 N = 0 N

a = ∑F/m

a = 0/27 kg

a = 0 m/s²

Learn more about net force here: brainly.com/question/14361879

#SPJ1

7 0
2 years ago
true or false Both the large loose rocks and the small loose rocks used to be part of earth's solid rock layer
salantis [7]
Hello Micu212006 


Question: <span> Both the large loose rocks and the small loose rocks used to be part of earth's solid rock layer
</span><span>
Answer: True


Hope This Helps!
-Chris </span>
8 0
3 years ago
Energy from the Sun arrives at the top of the Earth’s atmosphere with an intensity of 1.30kW/m21.30⁢kW/m2. How long does it take
vivado [14]

Answer:

T=1.384×10⁶seconds

Explanation:

Given data

p (Intensity)=1.30 kw/m²

E (Energy)=1.8×10⁹ J

A (Area)=1.00 m²

T (Time required)=?

Solution

E=PT   ................eq(i)

where E is energy

P is radiation power

T is time

Radiating Power is given as

P=pA

Where p is intensity

A is Area

Put P=pA in eq(i) we get

E=pAT

T=E/pA

T=\frac{(1.8*10^{9}}{(1.30*10^{3} )*(1.00)}  )\\T=1.38*10^{6} seconds

3 0
3 years ago
what happens to light when it falls upon a material that has a natural frequency equal to the frequency of the light?
mixas84 [53]

The energy from the light is transferred to the material, causing it to vibrate and absorb the light.

What is energy?
In physics, energy is the quantitative quality that is transmitted to the a body or a physical system, and is discernible in the work performed as well as in the form of light and heat. The law of conservation states that although energy can change its form, it cannot be created or destroyed. Energy is indeed a conserved quantity. The International System of Units' (SI's) joule is the measurement unit for energy (J). A moving object's kinetic energy, a solid object's elastic energy, chemical energy caused by chemical reactions, and the potential energy that an object stores (for instance because of its position inside a field) are examples of common forms of energy.

When light falls upon a material that has a natural frequency equal to the frequency of the light, the light will be absorbed by the material. This is due to resonance, which occurs when the frequency of the light matches the natural frequency of the material. The energy from the light is transferred to the material, causing it to vibrate and absorb the light.

To learn more about energy
brainly.com/question/582060
#SPJ4

7 0
1 year ago
A spacecraft is moving past the earth at a constant speed of 0.60 times the speed of light. The astronaut measures the time inte
Afina-wow [57]

Answer:

the time interval that an earth observer measures is 4 seconds

Explanation:

Given the data in the question;

speed of the spacecraft as it moves past the is 0.6 times the speed of light

we know that speed of light c = 3 × 10⁸ m/s

so speed of spacecraft v = 0.6 × c = 0.6c

time interval between ticks of the spacecraft clock Δt₀ = 3.2 seconds

Now, from time dilation;

t = Δt₀ / √( 1 - ( v² / c² ) )

t = Δt₀ / √( 1 - ( v/c )² )

we substitute

t = 3.2 / √( 1 - ( 0.6c / c )² )

t = 3.2 / √( 1 - ( 0.6 )² )

t = 3.2 / √( 1 - 0.36 )

t = 3.2 / √0.64

t = 3.2 / 0.8

t = 4 seconds

Therefore, the time interval that an earth observer measures is 4 seconds

6 0
3 years ago
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