To develop this problem, it is necessary to apply the concepts related to the description of the movement through the kinematic trajectory equations, which include displacement, velocity and acceleration.
The trajectory equation from the motion kinematic equations is given by
Where,
a = acceleration
t = time
= Initial velocity
= initial position
In addition to this we know that speed, speed is the change of position in relation to time. So
x = Displacement
t = time
With the data we have we can find the time as well
With the equation of motion and considering that we have no initial position, that the initial velocity is also zero then and that the acceleration is gravity,
Therefore the vertical distance that the ball drops as it moves from the pitcher to the catcher is 1.46m.
Complete question:
A 200 g load attached to a horizontal spring moves in simple harmonic motion with a period of 0.410 s. The total mechanical energy of the spring–load system is 2.00 J. Find
(a) the force constant of the spring and (b) the amplitude of the motion.
Answer:
(a) the force constant of the spring = 47 N/m
(b) the amplitude of the motion = 0.292 m
Explanation:
Given;
mass of the spring, m = 200g = 0.2 kg
period of oscillation, T = 0.410 s
total mechanical energy of the spring, E = 2 J
The angular speed is calculated as follows;
(a) the force constant of the spring
(b) the amplitude of the motion
E = ¹/₂kA²
2E = kA²
A² = 2E/k
<h3>Answer:</h3>
- 24.5 km/h
- 4 17/27 m/s
- 11/3 m/s²
<h3>Explanation:</h3>
1. The average speed is the ratio of total distance to total time:
... speed = distance/time = (92 km +55 km)/(3 h +3h) = (147 km)/(6 h)
... = 24.5 km/h
2. speed = distance/time = (125 m)/(27 s) = 4 17/27 m/s
3. a = ∆v/∆t = (15 m/s -4 m/s)/(3 s) = 11/3 m/s²
Explanation:
Work Done = Force * Displacement
= (4N)(10m) = 40J.
Power = Work Done / Time
= (40J)/(20s) = 2J/s = 2 Nm/sec.
Answer:
false
Explanation:
bc the faster car has more inertia (i dont think im correct)
not sure but feels like it
