The project's criteria.

A medium-sized jet has a 3.8-mm-diameter fuselage and a loaded mass of 85,000 kg. The drag on an airplane is primarily due to th

SCORPION-xisa [38]

Answer:

$F_{thrust}$ ≅ 111 KN

Explanation:

Given that;

A medium-sized jet has a 3.8-mm-diameter i.e diameter (d) = 3.8

mass = 85,000 kg

drag co-efficient (C) = 0.37

(velocity (v)= 230 m/s

density (ρ) = 1.0 kg/m³

To calculate the thrust; we need to determine the relation of the drag force; which is given as:

$F_{drag}$ = $\frac{1}{2}$ × CρAv²

where;

ρ = density of air wind.

C = drag co-efficient

A = Area of the jet

v = velocity of the jet

From the question, we can deduce that the jet is in motion with a constant speed; as such: the net force acting on the jet in the air = 0

SO, $F_{drag}-F_{thrust} = 0$

We can as well say:

$F_{drag}= F_{thrust}$

We can now replace $F_{thrust} with F_{drag}$ in the above equation.

Therefore, $F_{thrust}$ = $\frac{1}{2}$ × CρAv²

The A which stands as the area of the jet is given by the formula:

$A=\frac{\pi d^2}{4}$

We can now have a new equation after substituting our A into the previous equation as:

$F_{thrust}$ = $\frac{1}{2}$ × Cρ $(\frac{\pi d^2}{4})v^2$

Substituting our data from above; we have:

$F_{thrust}$ = $\frac{1}{2}$ × $(0.37)(1.0kg/m^3)(\frac{\pi(3.8m)^2 }{4})(230m/s)^2$

$F_{thrust}$ = $\frac{1}{8} (0.37)(1.0kg/m^3)({\pi(3.8m)^2 })(230m/s)^2$

$F_{thrust}$ = 110,990N

$F_{thrust}$ in N (newton) to KN (kilo-newton) will be:

$F_{thrust}$ = $(110,990N)*\frac{1KN}{1,000N}$

$F_{thrust}$ = 110.990 KN

$F_{thrust}$ ≅ 111 KN

In conclusion, the jet engine needed to provide 111 KN thrust in order to cruise at 230 m/s at an altitude where the air density is 1.0 kg/m³.

5 0

3 years ago

what do we call a landslide in which fine-grained soil moves cohesively but with extensive internal shearing?

pogonyaev

It is called an earth flow

5 0

3 years ago

Basil is installing a system in Toronto, Ontario where they are wide temperature variations. What is the TD of the system he’s i

marysya [2.9K]

In places with cold winters, space heating systems have a fundamental role in buildings. Without them, indoor temperatures would quickly become unsuitable for human occupancy. The local weather is one of the most important factors when designing a heating system; if two identical buildings are developed in Miami FL and New York City, the heating load will be much higher for the NYC property.

4 0

3 years ago

explain each of the following kinds of rockets: Solid-Fuel Rocket, Liquid-Fuel Rocket, Ion Rocket and Plasma Rocket.

Rudik [331]

Answer:

ur answer friend

Explanation:

answer

Solid-Fuel Rocket - a solid-propellant rocket or solid rocket is a rocket with a rocket engine that uses solid propellants. The earliest rockets were solid-fuel rockets powered by gunpowder; they were used in warfare by the Chinese, Indians, Mongols and Persians, as early as 13th century.

Liquid-Fuel Rocket - a liquid-propellant rocket or liquid rocket utilizes a rocket engine that use liqiud propellants. An inert gas stored in a tank at a high pressure is sometimes used instead of pumps in simpler small engines to force the propellants into the combustion chamber.

Ion Rocket - an ion thruster or ion drive is a form of electric propulsion used for spacecraft propulsion. It creates thrust by accelerating ions using electricity. The Deep Space 1 spacecraft, powered by an ion thruster, changed velocity by 4.3 km/s ( 9600 mph ) while consuming less than 74 kg ( 163 lb ) of xenon.

Plasma Rocket - in this type of rocket, a combination of electric and magnetic fields are used to break down the atoms and molecules of a propellant gas into a collection of particles that have either a positive charge (ions) or a negative charge (electrons). In other words, the propellant gas becomes a plasma.

I think its helpful to you

Please mark as brainliest answer

5 0

3 years ago

Your program must output each student’s name in the form: last name followed by a comma, followed by a space, followed by the fi

Reptile [31]

Answer:

#include <iostream>

#include <string>

#include <fstream>

using namespace std;

char getStudentGrade(int testScore);

//Declare constant max students in file 10

const int maxStudents = 10;

struct StudentType

{

string studentFName;

string studentLName;

int testScore;

char grade;

};

void readStudentData(StudentType students[]){

int i = 0;

ifstream infile;

infile.open("inputStudentData.txt");

while (!infile.eof())

{

infile >> students[i].studentFName;

infile >> students[i].studentLName;

infile >> students[i].testScore;

students[i].grade = getStudentGrade(students[i].testScore);

i++;

}

char getStudentGrade(int testScore){

char grade;

if(testScore >= 80) {

grade = 'A';

}

else if(testScore >= 60) {

grade = 'B';

}

else if(testScore >= 50) {

grade = 'C';

}

else if(testScore >= 40) {

grade = 'D';

}

else {

grade = 'F';

}

return grade;

}

int main()

{

StudentType students[10];

readStudentData(students);

for(int i=0;i<maxStudents;i++) {

students[i].grade = getStudentGrade(students[i].testScore);

}

for(int i=0; i<maxStudents; i++){

cout << students[i].studentLName <<", " << students[i].studentFName << " " << students[i].grade << endl;

}

ofstream outputFile;

outputFile.open ("outputStudentData.txt");

for(int i=0; i<maxStudents; i++){

outputFile << students[i].studentLName <<", " << students[i].studentFName << " " << students[i].grade << endl;

}

outputFile.close();

return 0;

}

3 0

3 years ago