you must check that the head gasket is seated correctly and is not dislodged or slightly moved in some way or youl result in oil or coolant in the cylinders and loss of compression is possible to or a vacum leak in 1 or more cylinders
Answer:
Enthalpy
Explanation:
Thermodynamic properties could be Intensive or extensive properties. Intensive properties are those that don't depend on the quantity of matter. Examples are pressure & temperature. Meanwhile, extensive properties are those whose values depend on the mass of the system. Examples are Energy, enthalpy and volume.
Now, in turbines in thermodynamics, the work done is produced by the flow required to turn the turbine and shaft. Recall that from the law of conservation of energy, the work in the turbine per mass airflow would be equal to the change in specific enthalpy of the flow from the entrance to the exit point of the turbine.
Thus, the property required to determine the work is Enthalpy.
Q)The shear flow at a point is given by q = 1 of 2 An I-beam has a flange width b = 200 mm , height h = 200 mm , web thickness tw = 8 mm, and flange thickness t = 12 mm, For the given point The shear flow at the point depends on the value of Q for the portion of the upper flange to the right of the point. Calculate the value of Q. Express your answer with appropriate units to three significant figures.( <u>I have also attached the diagram for better understanding)</u>
Answer:
Q = 56400 mm^3
Explanation:
<u>I have given the explanation in the attached file below.</u>
In surface mining, stripping ratio or strip ratio refers to the amount of waste (or overburden) that must be removed to release a given ore quantity.
Answer:
R = 31.9 x 10^(6) At/Wb
So option A is correct
Explanation:
Reluctance is obtained by dividing the length of the magnetic path L by the permeability times the cross-sectional area A
Thus; R = L/μA,
Now from the question,
L = 4m
r_1 = 1.75cm = 0.0175m
r_2 = 2.2cm = 0.022m
So Area will be A_2 - A_1
Thus = π(r_2)² - π(r_1)²
A = π(0.0225)² - π(0.0175)²
A = π[0.0002]
A = 6.28 x 10^(-4) m²
We are given that;
L = 4m
μ_steel = 2 x 10^(-4) Wb/At - m
Thus, reluctance is calculated as;
R = 4/(2 x 10^(-4) x 6.28x 10^(-4))
R = 0.319 x 10^(8) At/Wb
R = 31.9 x 10^(6) At/Wb
