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lidiya [134]
2 years ago
12

What's the geometry of sp³ hybridization ~ ​

Chemistry
1 answer:
Angelina_Jolie [31]2 years ago
3 0

Answer:

For sp3 hybridized central atoms the only possible molecular geometry is tetrahedral.

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What is the difference between 2 ml of salt and 2.0 ml of salt?
faltersainse [42]

Answer:

The 2 ml and 2.0 ml is the same thing.

8 0
3 years ago
1. Which is not true of binary compounds?
nignag [31]
Pretty sure it's b but not an definitely
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3 years ago
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ʕ•ᴥ•ʔ Which type of reaction occurs between an acid and a base and results in the formation of a salt and water? ʕ•ᴥ•ʔ
Nataliya [291]
The answer would be D. because when an acid and base mix the start to cancel each other out causing it to neutralize
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A specific brand of gourmet chocolate candy contains 7.00 g of dietary fat in each 22.7-gpiece. How many kilograms of dietary fa
Genrish500 [490]

Answer:  0.14 kg

Explanation:

Gourmet chocolate candy contains 7.00 g of dietary fat in each 22.7-g piece

That is 1 piece of candy weighs 22.7 g and contains 7.00 g of dietary fat

Converting the mass in pounds to kg  

1 lb = 0.45 kg = 450 grams    (1kg=1000g)

Number of pieces = \frac{450}{22.7g}=20pieces

1 piece contains = 7 g of dietary fat

Thus 30 pieces would contain =\frac{7}{1}\times 20=140g of dietary fat

1 g = 0.001 kg

Thus 140 grams =\frac{0.001}{1}\times 140=0.14kg

Thus 0.14 kg of dietary fat are in a box containing 1.00 lb of candy.

5 0
3 years ago
What volume, in milliliters, of a 0.997 M KOH solution is needed to neutralize 30.0 mL of 0.0400 M HCl?
deff fn [24]

Answer:

1.2 mL

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated:

HCl + KOH —> KCl + H₂O

From the balanced equation,

Mole ratio of the acid, HCl (nₐ) = 1

Mole ratio of base, KOH (n₆) = 1

Finally, we shall determine the volume of the base, KOH needed to neutralize the acid, HCl as follow:

Molarity of base, KOH (M₆) = 0.997 M

Volume of acid, HCl (Vₐ) = 30 mL

Molarity of acid, HCl (Mₐ) = 0.0400 M

Volume of base, KOH (V₆) =?

MₐVₐ / M₆V₆ = nₐ/n₆

0.04 × 30 / 0.997 × V₆ = 1/1

1.2 / 0.997 × V₆ = 1

Cross multiply

0.997 × V₆ = 1.2

Divide both side by 0.997

V₆ = 1.2 / 0.997

V₆ = 1.2 mL

Thus, the volume of the base, KOH needed to neutralize the acid is 1.2 mL.

7 0
3 years ago
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