0.5 mg/mL would be expressed as 500 ug/uL
Answer:
The answer to your question is: first option.
Explanation:
What is an aqueous solution?
Aqueous solution is a solution which solvent is water and is homogeneous.
a) An aqueous solution is a homogeneous mixture of a substance with water. This is the correct definition of aqueous solution because it mentions the characteristics of this kind of solutions.
b) An aqueous solution is a dispersoid solution. This option is wrong, it is a homogeneous solution, and the description do not mention water.
c) An aqueous solution is a mixture of a liquid substances. Aqueous solution is a mixture but one of the components is water not a liquid substance.
d) An aqueous solution is a heterogeneous mixture of a substance with water. Aqueous solution is homogeneous not heterogeneous, this option is wrong.
True because if anything is moving it is in motion. And because horizontal is similar to projectile!
Answer:
6.00%
Explanation:
Step 1: Given data
Accepted value for the number of calories in a Bananas Foster: 300 calories
Measured value for the number of calories in a Bananas Foster: 318 calories
Step 2: Calculate the percent error in the measure
We will use the following expression.
%error = |accepted value - experimental value|/ accepted value × 100%
%error = |300 cal - 318 cal|/ 300 cal × 100% = 6.00%
The question is incomplete, here is the complete question:
At elevated temperature, nitrogen dioxide decomposes to nitrogen oxide and oxygen gas
The reaction is second order for 
with a rate constant of 
at 300°C. If the initial [NO₂] is 0.260 M, it will take ________ s for the concentration to drop to 0.150 M
a) 1.01 b) 5.19 c) 0.299 d) 0.0880 e) 3.34
<u>Answer:</u> The time taken is 5.19 seconds
<u>Explanation:</u>
The integrated rate law equation for second order reaction follows:
![k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B1%7D%7Bt%7D%5Cleft%20%28%5Cfrac%7B1%7D%7B%5BA%5D%7D-%5Cfrac%7B1%7D%7B%5BA%5D_o%7D%5Cright%29)
where,
k = rate constant =
t = time taken = ?
[A] = concentration of substance after time 't' = 0.150 M
![[A]_o](https://tex.z-dn.net/?f=%5BA%5D_o)
= Initial concentration = 0.260 M
Putting values in above equation, we get:
Hence, the time taken is 5.19 seconds
