All categories

3 years ago

What numbers indicate an acid?

2 answers:

5 0

Any pH level of 1-6 would be considered an acid. If the pH level is 7 it would be neutral, then anything above a level of 7 would be a base.

Vlad [161]3 years ago

3 0

The answers that indicate acids are 1--6.9

You might be interested in

Calculate the molar mass of B(NO3)3 ?

Stella [2.4K]

The molar mass of B(NO₃)₃ - Boron nitrate : 196.822 g/mol

<h3>Further explanation</h3>

In stochiometry therein includes

<em>Relative atomic mass (Ar) and relative molecular mass / molar mass (M) </em>

So the molar mass of a compound is given by the sum of the relative atomic mass of Ar

M AxBy = (x.Ar A + y. Ar B)

The molar mass of B(NO₃)₃ - Boron nitrate :

M B(NO₃)₃ = Ar B + 3. Ar N + 9.Ar O

M B(NO₃)₃ = 10.811 + 3. 14,0067 + 9. 15,999

M B(NO₃)₃ = 196.822 g/mol

7 0

2 years ago

The heavier a gas molecule,

mr_godi [17]

Answer:

Explanation:

logic

3 0

3 years ago

All of the following are exothermic reactions except,

monitta

Exothermic reactions release heat the surrounding. So Freezing?

8 0

3 years ago

Write the chemical formula for the cation present in the aqueous solution of cuso4.

Inessa05 [86]

The ionic compounds on dissolving in aqueous solution dissociate into their respective ions that are cations and anions.

The ions present in the aqueous solution of $CuSO_4$ are $Cu^{2+}$ and $SO_{4}^{2-}$ .

So, the chemical formula of the cation present in the aqueous solution of $CuSO_4$ is $Cu^{2+}$ .

4 0

3 years ago

Hypochlorous acid decays in the presence of ultraviolet radiation. Assume that degradation occurs accord- ing to first-order kin

Dennis_Churaev [7]

Answer:

35.75 days

Explanation:

From the given information:

For first-order kinetics, the rate law can be expressed as:

$\mathsf{In \dfrac{C}{C_o} = -kt}$

Given that:

the rate degradation constant = 0.12 / day

current concentration C = 0.05 mg/L

initial concentration C₀ = 3.65 mg/L

$\mathsf{In( \dfrac{0.05}{3.65})= -(0.12) t}$

㏑(0.01369863014) = -(0.12) t

-4.29 = -(0.12)

t = -4.29/-0.12

t = 35.75 days

3 0

3 years ago