Answer:
35.68g CO2
Explanation:
we use the combustion equation with CH4:
CH4+ O2= CO2 + H2O
And then balance it:
CH4+ 2O2= CO2 + 2H2O
Using this equation we can use sociometry:

We know that 16.032 is how many grams there are in one mole of CH4 by adding the weights of the atoms (12 +1.008+1.008+1.008+1.008). These weights can be found on the periodic table. The same goes for the amount of grams per CO2.
The important thing about sociometry is to make sure your units cancel out until you are only left with the unit you want. If grams of CH4 is in the numerator, the next fraction you multiply by should have grams of Ch4 in the denominator. If moles of CO2 are in the numerator, the next fraction should have moles of CO2 in the denominator.
Weigh them both and there you go
Answer : The correct expression for equilibrium constant will be, ![K=[O_2]^5](https://tex.z-dn.net/?f=K%3D%5BO_2%5D%5E5)
Explanation :
Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.
The equilibrium expression for the reaction is determined by multiplying the concentrations of products and divided by the concentrations of the reactants and each concentration is raised to the power that is equal to the coefficient in the balanced reaction.
As we know that the concentrations of pure solids are constant that is they do not change. Thus, they are not included in the equilibrium expression.
The given equilibrium reaction is,

The expression of
will be,
![K=[O_2]^5](https://tex.z-dn.net/?f=K%3D%5BO_2%5D%5E5)
Therefore, the correct expression for equilibrium constant will be, ![K=[O_2]^5](https://tex.z-dn.net/?f=K%3D%5BO_2%5D%5E5)
I = average intensity of sunlight reaching at Madison = 2000 Js⁻¹m⁻²
A = area on which the light strike = 4.80 cm² = 4.80 x 10⁻⁴ m²
energy received per second by the area is given as
E = IA
inserting the values
E = (2000) (4.80 x 10⁻⁴)
E = 0.96 J
λ = wavelength of the photons in the sunlight = 510 x 10⁻⁹ m
c = speed of light = 3 x 10⁸ m/s
h = plank's constant = 6.63 x 10⁻³⁴ J-s
n = number of photons received per second
energy received per second is also given as
E = n h c /λ
inserting the values
0.96 = n (6.63 x 10⁻³⁴) (3 x 10⁸) /(510 x 10⁻⁹)
n = 2.5 x 10¹⁸ per second