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3 years ago

A moving object is in equilibrium. Which best describes the motion of the object if no forces change?

2 answers:

8 0

If the object is in equilibrium that means that the sum of the forces on it is zero and the net force is zero. If none of the forces changes then the object continues in constant uniform motion. That means constant speed in a straight line.

katrin2010 [14]3 years ago

5 0

Answer:

Uniform speed linear motion .

Explanation:

Any object can be in the state of equilibrium is sum of all the forces acting on it is zero means zero net force. If no forces change over it then the object will be uniform motion which means speed will remain constant. Best example for this situation is uniform motion along a straight line or uniform speed linear motion.

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I don’t understand I need help asap

hammer [34]

For the first question, you got them right, for the two you left blank, initial(beginning) velocity: 2 m/s the final velocity is: 12 m/s

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3 years ago

How can you use tweezers to separate a mixture

drek231 [11]

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5 0

3 years ago

Read 2 more answers

A container with volume 1.64 L is initially evacuated. Then it is filled with 0.226 g of N2N

vaieri [72.5K]

Answer:

0.015 atm

Explanation:

The pressure of the gas can be calculated using Ideal Gas Law:

$p = \frac{nRT}{V}$

Where:

n: is the number of moles of the gas

R: is the gas constant = 0.082 L*atm/(K*mol)

V: is the volume of the container = 1.64 L

T: is the temperature

We need to find the number of moles and the temperature. The number of moles is:

$n = \frac{m}{M}$

Where:

M: is the molar mass of the N₂ = 14.007 g/mol*2 = 28.014 g/mol

m: is the mass of the gas = 0.226 g

$n = \frac{0.226 g}{28.014 g/mol} = 8.07 \cdot 10^{-3} moles$

Now, the temperature can be found using the following equation:

$v_{rms} = \sqrt{\frac{3RT}{M}}$

Where:

R: is the gas constant = 0.082 L*atm/K*mol = 8.314 J/K*mol

$v_{rms}$ : is the root-mean-square speed of the gas = 182 m/s

By solving the above equation for T, we have:

$T = \frac{v_{rms}^{2}*M}{3R} = \frac{(182 m/s)^{2}*28.014 \cdot 10^{-3} Kg/mol}{3*8.314 J K^{-1}mol^{-1}} = 37.20 K$

Finally, we can find the pressure of the gas:

$p = \frac{nRT}{V} = \frac{8.07 \cdot 10^{-3} mol*0.082 L*atm* K^{-1}*mol^{-1}*37.20 K}{1.64 L} = 0.015 atm$

Therefore, the pressure of the gas is 0.015 atm.

I hope it helps you!

8 0

3 years ago

A 7300 N elevator is to be given an acceleration of 0.150g by connecting it to a cable of negligible weight wrapped around a tur

Firlakuza [10]

Answer:

α =18.75 rad/s²

Explanation:

Given that

Acceleration a = 0.15 g

We know that g =10 m/s²

a= 0.15 x 10 = 1.5 m/s²

d= 16 cm

Radius r= 8 cm

Lets take angular acceleration =α rad/s²

As we know that

a= α r

Now by putting the values

1.5 = α x 0.08

α =18.75 rad/s²

6 0

3 years ago

According to Charles' law, as the temperature of a given gas at constant pressure is increased, the volume will also

Alenkasestr [34]

A modern statement of Charles's law is: When the pressure on a sample of a dry gas is held constant, the Kelvin temperature and the volume will be in direct proportion. ... The equation shows that, as absolute temperature increases, the volume of the gas also increases in proportion.

i hope it will help

4 0

3 years ago