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2 years ago

Please help with some/all questions on this worksheet

Physics

1 answer:

Roman55 [17]2 years ago

5 0

A. Yes electricity is a fuel this is because protons are being displaced threw currents of electricity that are the used too charge a coil witch spins causing rotationional force And power too appropriate machine
B. Octane
C.one advantage is more power since octane is more combustable than electricity it makes gas or Diesel engines more powerful as too why there are no semi trucks being powered by electricity.
D. One disadvantage is effectively how well its fuel is spent gas is 69.78% less efficient

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Why does methane have a low boiling point?

svlad2 [7]

The molecules held together are to weak so the substance melt and boil at low points.

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3 years ago

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The brakes of an automobile are suddenly applied at the instant when its velocity is 20 m/s. If the automobile comes to a stop a

Gre4nikov [31]

Data:

Time (t) = 5 seconds
Final Velocity (v) = 0 [as the car comes to rest]
Initial velocity (u) = 20 m/s
Acceleration = ? (Negative because it is braking)

$Acceleration = \frac{v-u}{t}$
$Acceleration = \frac{0-20}{5}$
$\boxed{Acceleration = - 4m/s^2}$

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3 years ago

A 1.0-kg block and a 2.0-kg block are pressed together on a horizontal frictionless surface with a compressed very light spring

egoroff_w [7]

Answer:

4. both blocks will both have the same amount of kinetic energy.

Explanation:

When the blocks are released free from the compression force, the spring exerts equal and opposite force on each block but the block with heavier (double) mass will attain slower ( half ) speed as compared to the lighter block according to the law of inertia. This works in synchronization to energy conservation.

Spring force is given as:

$F=k.\Delta x$

where: $\Delta x=$ length of compression in the spring

We know kinetic energy is given by:

$KE=\frac{1}{2} m.v^2$

Hence the kinetic energy of both the blocks is equal when they are released to move free.

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4 years ago

A charged box (m=445 g, ????=+2.50 μC) is placed on a frictionless incline plane. Another charged box (????=+75.0 μC) is fixed i

victus00 [196]

The concept required to perform this exercise is given by the coulomb law.

The force expressed according to this law is given by

$F= \frac{kqQ}{r^2}$

Where,

$k = 8.99 * 10^9 N m^2 / C^2.$

q = charges of the objects

r= distance/radius

Our values are previously given, so

$q= 2.5*10^{-6}C\\Q= 75*10^{-6}C\\r=0.59$

Replacing,

$F=\frac{kqQ}{r^2}$

$F= \frac{(8.99 x 10^9)(2.5*10^{-6})(75*10^{-6})}{0.59^2}$

$F= 4.8423N$

The force acting on the block are given by,

$F-mgsin\theta = ma$

$a = \frac{F-mgsin\theta}{m}$

$a = \frac{4.8423-(0.445)(9.8)sin(35)}{0.445}$ $a = 10.31m/s^2$

Therefore the box is accelerated upward.

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3 years ago

A string of length 1.3 m is oscillating in a standing wave pattern. If the tension in the string is 430 N, the string has a mass

Vlad1618 [11]

To solve this problem we will use the concepts related to the speed of a string which is given by the applied voltage and the linear mass density of it. With the speed value we can find the fundamental frequency that will serve as a step to find the maximum speed through the relation of Amplitude and Angular Speed. So:

$v = \sqrt{\frac{T}{\mu_e}}$