calculate the spring constant if a weight of 250N is added to a spring which increases in length by 20cm
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a)If it takes the bird 18.0 minutes to fly 6 km away from the earth, the wind's speed will be 4 m/s.
b) The bird would need 7 minutes and 42 seconds to fly back 6 kilometers if he turned around and flew with the wind.
c)Compared to the 133.33 seconds it would take without the wind, the overall round-trip time is affected by the wind.
<h3>What is velocity?</h3>The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.
The given data in the problem is
A seagull flies at a velocity,
The time the bird takes,t=18.0 min
The distance traveled relative to the earth = 6.00 km
a)
The seagull's relative velocity with reference to the ground as;
Air velocity with reference to the ground is;
b)
If the bird turns around and flies with the wind, The time will he take to return 6.00 km is;
The time the bird takes;
c)\
The total round-trip time compared to what it would be with no wind. is;
The time for the round trip is;
Hence the wind's speed, the time bird would need to fly back the total round-trip time will be 4 m/s, 7 minutes and 42 seconds and 1333.33 sec.
To learn more about the velocity, refer to the link: brainly.com/question/862972.
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Answer:
Pressure applied by the man= 285103.125 or 41.35
Explanation:
Pressure is defined as the perpendicular force applied per unit area.
i.e.
Now,
where, = mass of the body(man) = 93 kg
= acceleration due to gravity of Earth = 9.81
covered is equal to the area of both stilts(a man generally stands on two feet)
therefore
and putting in the values, we get,
Now we need to convert to our required units:
(We can get the above result by individually converting kg to lb and meters to inches respectively)
Using the above relations we get,