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3 years ago

calculate the spring constant if a weight of 250N is added to a spring which increases in length by 20cm

Physics

1 answer:

ZanzabumX [31]3 years ago

8 0

Since, F = k . ∆x

Therefore, k = F / ∆x = 250 / 0.2 = 1250 N/m

(ps: convert 20 cm into 0.2 m)

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Answer:

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System of forces in balance

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Answer:

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T(K) = T( °C) + 273.15

So,

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V = 0.500 L

Using ideal gas equation as:

PV=nRT

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

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P × 0.500 L = 1 ×0.0821 L atm/ K mol × 301.15 K

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Using Van der Waal's equation

$\left(P+\frac{an^2}{V^2}\right)\left(V-nb\right)=nRT$

R = 0.0821 L atm/ K mol

Where, a and b are constants.

For Ar, given that:

So, a = 1.345 atm L² / mol²

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So,

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⇒P (real) = 47.47 atm

Difference in pressure = 49.45 atm - 47.47 atm = 1.98 atm

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