The breakdown of NO3 in the day leads to more consumption of N2O5 in the day hence its concentration is greater at night than in the day.
<h3>What is equilibrium constant?</h3>
The equilibrium constant is a number that shows how much reactants are converted to products in a reaction. It is often shown as capital letter K in English.
Given the situation described in the question, we know that the concentration of N205 will be higher at night, because the decomposition of NO3(g) in the daytime will result in an increase in the rate of consumption of N2O5(g) to reform NO3(g).
Learn more about equilibrium constant: brainly.com/question/17960050
Answer:
Cell Type I: Animal cell surrounded by a plasma membrane only.
Cell Type II: Plant cell surrounded by a plasma membrane and a cell wall.
Explanation:
Hello,
In this case, we must remember that animal cells are covered only by a plasma membrane, which is not enough to keep the cell from bursting as no limit for the inlet salt is established, causing it both to swell and burst. On the other hand, plant cells are covered by both a plasma membrane and a cell wall which contributive effect allow the inlet of the salt but prevent the cell to burst as the cell wall is rigid. In such a way, based on the described situation, one infers that the cell type I is an animal cell surrounded by a plasma membrane only the cell type II is a plant cell surrounded by a plasma membrane and a cell wall.
Best regards.
changing the bonds changes the mass.
your welcome!
Answer:
One can determine the specific heat of the metal through using the clarimeter, water, thermometer and using heat equations.
Explanation:
You can learn about heat effects and calorimetery through a simple experiment by boiling water and heating up the metal in it. Then, pour it into your calorimeter and the heat will flow from the metal to the water. The two equlibria will meet: the metal will loose heat into its surroundings (the water) and teh water will absorb the heat. The heat flow for the water is the same as it is for the metal, the only difference being is the negative sign indicating the loss of the heat of the metal.
In terms of theromdynamics, we can deteremine the heat flow for the metal becasue it would be equal to the mangnitued but opposite in direction. Thus, we can say that the specific heat of water qH2O = -qmetal.
