Answer:
compaction and cementation
I love science by the way
Answer:
S(metal) = 0.66J/g°C
Explanation:
We can find specific heat of a material, S, using the equation:
q = m*S*ΔT
<em>Where q is change in heat, m is the mass of the substance, S specific heat and ΔT change in temperature.</em>
The heat given by the metal is equal to the heat that water absorbs, that is:
m(Metal)*S(metal)*ΔT(Metal) = m(Water)*S(water)*ΔT(water)
<em>Where:</em>
m(Metal) = 76.0g
S(metal) = ?
ΔT(Metal) = 96.0°C-31.0°C = 65.0°C
m(Water) = 120.0g
S(water) = 4.184J/g°C
ΔT(water) = 31.0°C-24.5°C = 6.5°C
Replacing:
76.0g*S(metal)*65.0°C = 120.0g*4.184J/g°C*6.5°C
S(metal) = 0.66J/g°C
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The law of conservation applies because the energy is not been created or destroyed. The energy that the metal gives is absorbed by the water.
D is the only choice here that is appropriate given neutrons' lack of charge
Answer:
What happens when electrons in atoms absorb or release energy? When electrons absorb or release energy, their electrons can move to higher or lower energy levels. These electrons lose energy by emitting light when they return to lower energy levels.
Explanation:
i really hope this helps
Answer:
A thermochemical equation for the combustion of propane (C3H8)(C3H8) is written as follows:
C3H8(l)+5O2(g)→3CO2(g)+4H2O(g);ΔH∘rxnC3H8(l)+5O2(g)→3CO2(g)+4H2O(g);ΔHrxn∘ = -2202.0 kJ/mol
The value given for ΔH∘rxnΔHrxn∘ means that:
a. the reaction of one mole of propane absorbs 2202 kJ of energy from the surroundings.
b. the reaction is endothermic.
c. the enthalpy of formation of propane is 2202 kJ/mol.
d. the reaction of one mole of propane releases 2202 kJ of energy to the surroundings.
e. None of these.
