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2 years ago

The quarks that compose a baryon may have charges of:.

1 answer:

3 0

The quarks that compose a baryon may have charges of +(2/3)e and -(1/3)e which means have negative and positive charges.

<h3>What are quarks?</h3>

Quarks are the most fundamental particles that make up the atomic nucleus. All solid matter that we know is made of three particles, which are the up and down quarks, 'u' and 'd', and the electron.

Quark is one of the two basic elements that make up matter and is the only one of the particles that interacts through all four fundamental forces.

See more about quarks at brainly.com/question/1444547

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If oxygen and steel wool are combined is it a physical change or chemical change?

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I think it would be a chemical change.

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A charged particle enters a uniform magnetic field B with a velocity v at right angles to the field. It moves in a circle with p

alukav5142 [94]

A) d. 10T

When a charged particle moves at right angle to a uniform magnetic field, it experiences a force whose magnitude os given by

$F=qvB$

where q is the charge of the particle, v is the velocity, B is the strength of the magnetic field.

This force acts as a centripetal force, keeping the particle in a circular motion - so we can write

$qvB = \frac{mv^2}{r}$

which can be rewritten as

$v=\frac{qB}{mr}$

The velocity can be rewritten as the ratio between the lenght of the circumference and the period of revolution (T):

$\frac{2\pi r}{T}=\frac{qB}{mr}$

So, we get:

$T=\frac{2\pi m r^2}{qB}$

We see that this the period of revolution is directly proportional to the mass of the particle: therefore, if the second particle is 10 times as massive, then its period will be 10 times longer.

B) $a. f/10$

The frequency of revolution of a particle in uniform circular motion is

$f=\frac{1}{T}$

where

f is the frequency

T is the period

We see that the frequency is inversely proportional to the period. Therefore, if the period of the more massive particle is 10 times that of the smaller particle:

T' = 10 T

Then its frequency of revolution will be:

$f'=\frac{1}{T'}=\frac{1}{(10T)}=\frac{f}{10}$

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3 years ago