Answer:
Cost of 1000 kilowatt hour = 6000 cents
Explanation:
Given that
Electricity cost is 6 cents per kilowatt hour.
And we have to found out the cost for one megawatt hour
We know that
1 kilowatt = 1000 watt
1 megawatt = = 1000000 watt
1 megawatt = 1000 kilowatt
1 megawatt hour = 1000 kilowatt hour
Given that cost of 1 kilowatt hour = 6 cents
So the cost of 1000 kilowatt hour = 6 x 1000 cents
Cost of 1000 kilowatt hour = 6000 cents
Answer:
The least uncertainty in the momentum component px is 1 × 10⁻²³ kg.m.s⁻¹.
Explanation:
According to Heisenberg's uncertainty principle, the uncertainty in the position of an electron (σx) and the uncertainty in its linear momentum (σpx) are complementary variables and are related through the following expression.
σx . σpx ≥ h/4π
where,
h is the Planck´s constant
If σx = 5 × 10⁻¹²m,
5 × 10⁻¹²m . σpx ≥ 6.63 × 10⁻³⁴ kg.m².s⁻¹/4π
σpx ≥ 1 × 10⁻²³ kg.m.s⁻¹
I believe it isa refraction. hope this helps
Answer:
No
Explanation:
The statement is implying that if you do a certain amount of work, you're entitled to do a certain amount of work. Sometimes, work doesn't entitle you a reward.
Answer:
Velocity,v = 0.323 m/s
Explanation:
The acceleration of a particle is given by :
![a=-(0.1+sin\dfrac{x}{b})](https://tex.z-dn.net/?f=a%3D-%280.1%2Bsin%5Cdfrac%7Bx%7D%7Bb%7D%29)
b = 0.8 m when x = 0
Since,
![\int{v.dv}=\int{-(0.1+sin\dfrac{x}{b})}.dx](https://tex.z-dn.net/?f=%5Cint%7Bv.dv%7D%3D%5Cint%7B-%280.1%2Bsin%5Cdfrac%7Bx%7D%7Bb%7D%29%7D.dx)
![\dfrac{v^2}{2}=-[0.1x-0.8cos\dfrac{x}{0.8}]+c](https://tex.z-dn.net/?f=%5Cdfrac%7Bv%5E2%7D%7B2%7D%3D-%5B0.1x-0.8cos%5Cdfrac%7Bx%7D%7B0.8%7D%5D%2Bc)
At x = 0, v = 1 m/s
![\dfrac{1}{2}=0.8+c](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B2%7D%3D0.8%2Bc)
![c=-0.3](https://tex.z-dn.net/?f=c%3D-0.3)
![\dfrac{v^2}{2}=-[0.1x-0.8cos\dfrac{x}{0.8}]-0.3](https://tex.z-dn.net/?f=%5Cdfrac%7Bv%5E2%7D%7B2%7D%3D-%5B0.1x-0.8cos%5Cdfrac%7Bx%7D%7B0.8%7D%5D-0.3)
At x = -1 m
![\dfrac{v^2}{2}=-0.1(-1)+0.8cos\dfrac{(-1)}{0.8}-0.3](https://tex.z-dn.net/?f=%5Cdfrac%7Bv%5E2%7D%7B2%7D%3D-0.1%28-1%29%2B0.8cos%5Cdfrac%7B%28-1%29%7D%7B0.8%7D-0.3)
![{v^2}=0.1045](https://tex.z-dn.net/?f=%7Bv%5E2%7D%3D0.1045)
v = 0.323 m/s
So, the velocity of the particle is 0.323 m/s. Hence, this is the required solution.