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1 answer:
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The acceleration of the box is approximately
Explanation:
According to Newton's second law of motion, the net force acting on the box is equal to the product between its mass and its acceleration:
where
is the net force
m = 12.0 kg is the mass of the box
a is the acceleration
The net force can be written as
where
is the applied forward force
is the friction force
Combining the two equations,
And solving for the acceleration,
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1) The distance travelled by the electron is
2) The time taken is
Explanation:
1)
The electron in this problem is moving by uniformly accelerated motion (constant acceleration), so we can use the following suvat equation
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance travelled
For the electron in this problem,
is the initial velocity
v = 0 is the final velocity (it comes to a stop)
is the acceleration
Solving for s, we find the distance travelled:
2)
The total time taken for the electron in its motion can also be found by using another suvat equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time taken
Here we have
v = 0
And solving for t, we find the time taken:
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Answer:
The Initial vertical velocity is zero
Explanation:
Given that,
A book is pushed with an initial horizontal velocity, Vx = 5 m/s
According to projectile motion, the horizontal component of velocity i.e., in X-axis remains the same though out its path.
The vertical velocity varies i.e., the velocity towards the Y- axis.
The velocity of the falling book in its trajectory is the resultant velocity. Due to the action of gravity, it keeps on increasing with time.
The resultant velocity is given by relation
where
gt = Vy - vertical velocity
g - acceleration due to gravity
t - time
Since, the initial horizontal velocity at that instant is equal to the resultant velocity.
Vx = 5 m/s
= 5 m/s
So, on substituting in the above equation
Vy = 0 m/s
Therefore, the initial vertical velocity is equal to zero