Answer:
5.099 ohm
Explanation:
Let number of the turn of wire be
N = L/D
Where L is the length of the solenoid and d is the diameter 75 cm = 0.75m , 0.100 = 0.001m
N = 0.75/0.100
N = 750
Hence the number of turns of copper wire is 750
The expression for the length of the wire
L = N ( πD )
Where D is the diameter of the solenoid. And take 750 for N and 10.0cm for the diameter.
Hence, L = 750 ( π × 10/100 )
L = 750 ×3.142× 0.1
L = 235.65m
The resistance of the wire is given as : R = p 4l/πd×d
Where p is the resistivity of the wire
l is the length of the wire and
d is the diameter of the wire
Let l = 235.65m , p = 1.7×10~ -8
0.100cm = 0.001m for the diameter
R = 1.7×10~-8 { 4× 235.65 } / π × ( 0.001m* 0.001 m)
R = 0.000016024/ 3.142 × 0.000001
R = 0.000016024/0.000003142
R = 5.099 ohms