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ira [324]
3 years ago
10

Ron fills a beaker with glycerin (n = 1.473) to a depth of 5.0 cm. if he looks straight down through the glycerin surface, he wi

ll perceive the liquid to be what apparent depth?
Physics
1 answer:
Tju [1.3M]3 years ago
7 0

By law of refraction we know that image position and object positions are related to each other by following relation

\frac{\mu_1}{h_o} = \frac{\mu_2}{h_i}

here we know that

\mu_1 = 1.473

h_o = 5 cm

\mu_2 = 1

now by above formula

\frac{1.473}{5} = \frac{1}{h_i}

h_i = 3.39 cm

so apparent depth of the bottom is seen by the observer as h = 3.39 cm

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Answer: 131.92 m

Explanation: The problem give above is a conversion problem. To convert any measurement from one unit to another, we need a relation for the original units to that of the desired unit. This relation is called the conversion factor. It is used by multiplying or dividing the factor depending on what is the unit of the original measurement. For this case, we need to convert from ft^2 to m^2. The conversion factor would be 1 foot is equal to 0.3048 m. So, we would be getting the square of the factor and then multiply to the original value.

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A 66.5-kg hiker starts at an elevation of 1270 m and climbs to the top of a peak 2660 m high.
anyanavicka [17]

Answer

given,

mass of the hiker = 66.5 kg

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b) Minimum work require by the hiker will be equal to Δ PE = 905863 J

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Explanation:

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