Answer:
The speed of the stone just before it hits the ground is 18.54 m/s
Explanation:
Given that,
Initial speed of the stone, u = 8 m/s
The stone is thrown downward from a height of 14 m
We need to find the speed of the stone just before it hits the ground. It can be calculated using third equation of motion as :

v is the speed of the stone just before it hits the ground


v = 18.54 m/s
So, the speed of the stone just before it hits the ground is 18.54 m/s. Hence, this is the required solution.
One should never anchor in a narrow channel, until unless required very importantly. One should stay to the starboard side, and use a prolonged blast. The announcement must be done to alarm the nearby vessels, about your approach. The vessel should be kept at the outer limit of the starboard side.
Answer:
The best single equation in order to fin the acceleration is

Explanation:
The best single equation in order to find the acceleration is the following kinematics equation:

As the rocket start from the rest, the initial velocity value is zero. Then the acceleration value is:

Answer: 0.016 h
Explanation:

It is given that, biker has an average speed = 18 km/h
Total distance traveled = 0.30 km
Therefore, time taken by biker to travel this distance:

Thus, the biker takes 0.016 hours to travel the segment of 0.30 km at an average speed of 18 km/h.