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givi [52]
2 years ago
6

A balloon is charged until it has a voltage of v=9800V. A student reaches out and is shocked by a spark. The electric force does

W= 1x10^-6J of work transferring the charge.
a) Input an expression for the magnitude of charge transferred Q
b) What is the magnitude of the charge, in coulombs?
c) How many electrons is this?
Physics
1 answer:
alina1380 [7]2 years ago
6 0

a)]An expression for the magnitude of charge transferred Q is Q = W/V.

b) The magnitude of the charge, in coulombs is  1.02 x 10⁻⁹ Coulomb.

c) Number of electrons in this are 63.75 x 10⁸ electrons.

<h3>What are electrons?</h3>

The electrons are the spinning objects around the nucleus of the atom of the element in an orbit.

A balloon is charged until it has a voltage of v=9800V. A student reaches out and is shocked by a spark. The electric force does W= 1x10⁻⁶ J of work transferring the charge.

a) Work done = Charge x potential

W = Q x V

Q = W/V

b)Substitute the values into the expression, we have

|Q| =  1x10⁻⁶/9800

|Q| =  1.02 x 10⁻⁹ Coulomb

c) No of electrons  = total charge /charge on electron

n = 1.02 x 10⁻⁹/1.6 x 10⁻¹⁹

n = 63.75 x 10⁸ electrons

Learn more about electrons.

brainly.com/question/1255220

#SPJ1

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The coping method that involves changing the way you feel or emotionally react to a stressor is known as _________.
expeople1 [14]
The appropriate response is Emotion-centered coping. It is a particular system that was produced in the 1980s by the clinicians Susan Folkman and Richard Lazarus, and these methods concentrate on changing one's passionate response to an unpleasant or disquieting circumstance, for example, getting a finding of a terminal disease.
6 0
3 years ago
1 point
Hitman42 [59]
I believe it is Gravitational force, hope this helps
5 0
3 years ago
The volume of a gas is increased six times the original volume by heating it. If the original temperature of
OleMash [197]

The final temperature of the gas given the data from the question is 1527 °C

<h3>Data obtained from the question</h3>
  • Initial volume (V₁) = V
  • Initial temperature (T₁) = 27 °C = 27 + 273 = 300 K
  • Final volume (V₂) = 6V
  • Final temperature (T₂) =?

<h3>How to determine the new temperature </h3>

The final temperature of the gas can be obtained by using the Charles' law equation as illustrated below:

V₁ / T₁ = V₂ / T₂

V / 300 = 6V / T₂

Cross multiply

V × T₂ = 300 × 6V

Divide both side by V

T₂ = (300 × 6V) / V

T₂ = 1800 K

Subtract 273 from 1800 K to express in degree celsius

T₂ = 1800 – 273

T₂ = 1527 °C

Learn more about gas laws:

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6 0
2 years ago
A thin, light wire 75.1 cm long having a circular cross section 0.555 mm in diameter has a 25.4 kg weight attached to it, causin
seraphim [82]

Answer:

(a) 3.23×10⁸ N/m²

(b)  1.46×10⁻³

(c) 2.21×10¹¹ N/m²

Explanation:

(a) Stress = Force/Area.

Stress = F/A................ Equation 1

But,

F = mg................. Equation 2

Where m = mass, and g = acceleration due to gravity

A = πd²/4................. Equation 3

d = diameter of the circular cross section.

Substitute equation 2 and equation 3 into equation 1

Stress = 4mg/πd²............. Equation 4

Given: m = 25.4 kg, d = 0.555 mm = 0.000555 m

Constant: g = 9.8 m/s², π = 3.142

Substitute these values into equation 4

Stress = 4(25.4)(9.8)/(3.142×0.00555²)

Stress = 995.68/(3.08×10⁻⁶)

Stress = 3.23×10⁸ N/m²

(b)

Strain = ΔL/L.............. Equation 5

Where ΔL = extension, L = Length.

Given: ΔL = 1.1 mm = 0.0011 m, L = 75.1 cm = 0.751 m

Substitute into equation 5

Strain = 0.0011/0.751

Strain = 1.46×10⁻³.

(c)

Young modulus = Stress/Strain

Young modulus = 3.23×10⁸/ 1.46×10⁻³

Young modulus = 2.21×10¹¹ N/m²

3 0
3 years ago
A tennis ball (m=0.060 kg) is moving horizontally at 20 m/s toward a tennis player who hits it straight back at 26 m/s. What is
Rus_ich [418]

Answer:

0.36 kg-m/s

Explanation:

Given that,

Mass of a ball, m = 0.06 kg

Initial velocity of the ball, u = 20 m/s

Final velocity of the ball, v = 26 m/s

We need to find the change in momentum of the tennis ball. It is equal to the final momentum minus initial momentum

\Delta p=m(v-u)\\\\=0.06\times (26-20)\\\\=0.36\ kg-m/s

So, the change in momentum of the ball is 0.36 kg-m/s.

4 0
2 years ago
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