1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
givi [52]
1 year ago
6

A balloon is charged until it has a voltage of v=9800V. A student reaches out and is shocked by a spark. The electric force does

W= 1x10^-6J of work transferring the charge.
a) Input an expression for the magnitude of charge transferred Q
b) What is the magnitude of the charge, in coulombs?
c) How many electrons is this?
Physics
1 answer:
alina1380 [7]1 year ago
6 0

a)]An expression for the magnitude of charge transferred Q is Q = W/V.

b) The magnitude of the charge, in coulombs is  1.02 x 10⁻⁹ Coulomb.

c) Number of electrons in this are 63.75 x 10⁸ electrons.

<h3>What are electrons?</h3>

The electrons are the spinning objects around the nucleus of the atom of the element in an orbit.

A balloon is charged until it has a voltage of v=9800V. A student reaches out and is shocked by a spark. The electric force does W= 1x10⁻⁶ J of work transferring the charge.

a) Work done = Charge x potential

W = Q x V

Q = W/V

b)Substitute the values into the expression, we have

|Q| =  1x10⁻⁶/9800

|Q| =  1.02 x 10⁻⁹ Coulomb

c) No of electrons  = total charge /charge on electron

n = 1.02 x 10⁻⁹/1.6 x 10⁻¹⁹

n = 63.75 x 10⁸ electrons

Learn more about electrons.

brainly.com/question/1255220

#SPJ1

You might be interested in
Your companion on a train ride through Illinois notices that telephone poles near the tracks appear to be passing by very quickl
Nikitich [7]

Answer: Relative motion

Explanation: If two objects are moving either towards or away from each other with both having their velocities in a reference frame and someone is outside this reference frame seeing the motion of the two objects.

The observer ( in his own frame of reference) will measure a different velocity as opposed to the velocities of the two object in their own reference frame. p

Both the velocity measured by the observer in his own reference frame and the velocity of both object in their reference is correct.

Velocities of this nature that have varying values based on motion referenced to another body is known as relative velocity.

Motion of this nature is known as relative motion.

<em>Note that the word reference frame is simply any where the motion is occurring and the specified laws of motion is valid</em>

<em />

For this example of ours, the reference frame of the companion is the train and the telephone poles has their reference frame as the earth.

The companion will measure the velocity of the telephone poles relative to him and the velocity of the telephone pole relative to an observer outside the train will be of a different value.

6 0
2 years ago
10. What is the acceleration of a 1000 kg car subject to a 500 N net force?
Simora [160]

Answer:

0.5m/s^2

Explanation:

We can use the formula [ F = ma ] but solve for "a" since that is what we are looking for.

F = ma

F/m = a

We know the net force and mass so substitute those values and simplify.

500/1000 = 0.5m/s^2

Best of Luck!

3 0
2 years ago
A ball is thrown upwards at an unknown speed. in a time of
alexandr402 [8]

Answer:

a)  Initial speed of the ball = 14.45 m/s

b) At height 6 m speed of ball = 9.55 m/s

c) Maximum height reached = 10.65 m

Explanation:

a)  We have equation of motion s=ut+\frac{1}{2} at^2, where s is the displacement, u is the initial velocity, t is the time taken and a is the acceleration.

s = 6 m, t = 0.5 seconds, a = acceleration due to gravity value = -9.8m/s^2

 Substituting

    6=u*0.5-\frac{1}{2} *9.8*0.5^2\\ \\ u=14.45m/s

 Initial speed of the ball = 14.45 m/s

 b) We have equation of motion v^2=u^2+2as, where v is the final velocity

   s = 6 m, u = 14.45 m/s, a = -9.8m/s^2

    Substituting

        v^2=14.45^2-2*9.8*6\\ \\ v=9.55m/s

  So at height 6 m speed of ball = 9.55 m/s

c) We have equation of motion v^2=u^2+2as, where v is the final velocity

   u = 14.45 m/s, v =0 , a = -9.8m/s^2

   Substituting

     0^2=14.45^2-2*9.8*s\\ \\ s=10.65 m

  Maximum height reached = 10.65 m

8 0
3 years ago
Do mechanical waves transfer light energy?
Gekata [30.6K]
B ... A ... A ... B .
7 0
3 years ago
Suppose a free-fall ride at an amusement park starts at rest and is in free fall. What is the velocity of the ride after 2.3 s?
horsena [70]

Answer:

V = a * t = 9.8 m/s^2 * 2.3 s = 22.5 m/s   velocity after 2.3 s

S = 1/2 g t^2      since initial speed is zero

S = 1/2 * 9.8 m/s^2 * 5.29 s^2 = 25.9 m

8 0
2 years ago
Other questions:
  • A police officer in hot pursuit of a criminal drives her car through an unbanked circular (horizontal) turn of radius 300 m at a
    10·1 answer
  • Enter the expression 2cos2(θ)−1, where θ is the lowercase Greek letter theta.
    10·1 answer
  • Pulsars A. spin very rapidly when they're young. B. are the cause of gamma-ray bursts. C. spin very slowly when they're young, a
    12·1 answer
  • Two plane mirrors make the angle α = 46.0 ° α=46.0° between them. A ray of light incident on one of the mirrors is reflected and
    8·1 answer
  • Where do consumers get their nitrogen from?
    12·1 answer
  • A basketball has a mass of 601 g. Moving to the right and heading downward at an angle of 29 degree to the vertical, it hits the
    7·1 answer
  • Currently, the Sun is thought to be located in the galactic _____________ about ____________ the center of the galaxy.
    12·1 answer
  • Carlota does 2000 J of work on a machine. The machine does 500 J of work. What is the efficiency of the
    7·2 answers
  • Please hellp!!!!!!!!!!!!!!!!!!!!?
    10·2 answers
  • An objec with a mass of 7 kg accelerates 5m/s2 when an unknown force is applied to it.what is the magnitude of the unknown force
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!