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Vsevolod [243]
2 years ago
7

PLEASE HELP ME (JOULES)

Chemistry
1 answer:
Svetllana [295]2 years ago
8 0

Answer:

The answer is not 9.9 i used that and got it wrong

Explanation:

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Which of the following is an acid-base neutralization reaction?
algol13

Answer:

D

Explanation:

The reaction in which an acid reacts with a base to form salt and water is called acid base reaction.

here, HCL ( strong acid) reacts with KOH (strong base) and KCL (salt) and H2O (water) is formed.

3 0
2 years ago
What is the pressure of 0.5 mol of nitrogen gas in a 5 L container at 203 K
Ivan

Answer:

1.67 atm.

Explanation:

  • We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm (P = ??? atm).

V is the volume of the gas in L (V = 5.0 L).

n is the no. of moles of the gas in mol (n = 0.5 mol).

R is the general gas constant (R = 0.0821 L.atm/mol.K),

T is the temperature of the gas in K (T = 203 K).

∴ P = nRT/V = (0.5 mol)(0.0821 L.atm/mol.K)(203 K)/(5.0 L) = 1.67 atm.

3 0
3 years ago
Homogeneous mixture that does not settle out upon standing reflect light is an element. solid. hydrated.
andrey2020 [161]
Homogeneous mixture that does not settle out upon standing but which will reflect light is called COLLOIDS.
There are three types of homogeneous mixtures, these are: solutions, colloids and suspension. Colloids are usually distinguished by Tyndall effects. Light passing through a colloidal dispersion will be reflected.<span />
5 0
3 years ago
50 examples word equation with balanced chemical equarion​
gulaghasi [49]
This question may only be ansewered by frequent mattrrs
5 0
2 years ago
If a system performs 147 kJ of work while receiving 47 kJ of heat, what is change in its internal energy?
Verdich [7]

Answer:

-100 kJ

Explanation:

We can solve this problem by applying the first law of thermodynamics, which states that:

\Delta U = Q-W

where:

\Delta U is the change in internal energy of a system

Q is the heat absorbed/released by the system (it is positive if absorbed by the system, negative if released by the system)

W is the work done by the system (it is positive if done by the system, negative if done on the system)

For the system in this problem we have:

W = +147 kJ is the work done by the system

Q = +47 kJ is the heat absorbed by the system

So , its change in internal energy is:

\Delta U = +47 - (+147) =-100 kJ

6 0
3 years ago
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