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Arlecino [84]
3 years ago
11

A certain element has only two naturally occurring isotopes: one with 18 neutrons and the other with 20 neutrons. The element fo

rms I- charged ions when in ionic compounds. Predict the identity of the element. What number of electrons does the charged ion have?
Chemistry
1 answer:
melamori03 [73]3 years ago
7 0

Answer:

[Cl-18]⁻ & [Cl-20]⁻

Explanation:

By definition isotopes are elements with the same number of protons by different number of neutrons. Elements X-18 & X-20 have 17 protons and represent Chlorine isotopes Cl-18 & Cl-20 each with 17 protons and 18 electrons to give the isotopes a -1 oxidation state. Both isotope of chlorine have 7 electron in its valence shell and 10 electrons in its core structure.  Gaining 1 electron fills the valence octet and establishes a -1 oxidation state.

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An unknown diprotic acid (H2A) requires 44.391 mL of 0.111 M NaOH to completely neutralize a 0.58 g sample. Calculate the approx
Anna [14]

Answer:

M=235.42g/mol

Explanation:

Hello!

In this case, given this is an acid-base neutralization and we are considering a diprotic acid, we can write the following mole-mole relationship:

2n_{acid}=n_{base}

It means that the moles of acid can be computed given the volume and concentration of NaOH:

n_{acid}=\frac{M_{base}V_{base}}{2} =\frac{0.044391L*0.111mol/L}{2} \\\\n_{acid}=2.46x10^{-4}mol

It means that the approximate molar mass of the acid is:

M=\frac{m_{acid}}{n_{acid}} \\\\M=\frac{m_{acid}}{n_{acid}} =\frac{0.58g}{2.46x10^{-3}mol}\\\\M=235.42g/mol

Best regards!

5 0
3 years ago
Which of the following is an example of anaerobic respiration?
Andrews [41]
Respiring while swimming underwater
Because anaerobic respiration means respiration with no oxygen, and there is no oxygen underwater
8 0
3 years ago
In the chemical reaction below, what is the product?<br> C + O2 + CO2
Tema [17]
You’ll need to be sure to count all the atoms in each side of the chemical equation.
7 0
3 years ago
A sample of sodium-24 with an activity of 14 mCi is used to study the rate of blood flow in the circulatory system. If sodium-24
SOVA2 [1]

Answer:

See explanation

Explanation:

From;

0.693/t1/2 = 2.303/t log (Ao/A)

Where;

t1/2 = half life of the sodium-24

t = time taken

Ao = initial activity of sodium-24

A= activity of sodium-24 at time t

a)

0.693/15 = 2.303/15 log (14/A)

0.0462 = 0.1535 log (14/A)

0.0462/0.1535 =  log (14/A)

log (14/A) = 0.0462/0.1535

14/A = Antilog(0.3)

14/A= 1.995

A = 14/1.995

A = 7.0 mCi

b)

0.693/15 = 2.303/30 log (14/A)

0.0462 =0.0768 log(14/A)

0.0462/0.0768 =log (14/A)

(14/A) =Antilog (0.6)

A = 14/Antilog (0.6)

A = 3.5 mCi

c)

0.693/15 = 2.303/45 log (14/A)

0.0462= 0.0512 log (14/A)

log (14/A) = 0.0462/0.0512

log (14/A) = 0.9

(14/A) = Antilog (0.9)

A= 14/Antilog (0.9)

A = 14/7.9

A = 1.77  mCi

d)

2.5 days = 2.5 * 24 hours = 60 hours

0.693/15 = 2.303/60 log (14/A)

0.0462 = 0.03838 log (14/A)

log (14/A) = 0.0462/0.03838

(14/A) = Antilog(1.2)

A= 14/Antilog(1.2)

A = 14/15.8

A = 0.886 mCi

Note that activity (A) decreases as time increases.

5 0
3 years ago
For the following SN2 reaction, draw the organic and inorganic products of the reaction, and identify the nucleophile, substrate
Sauron [17]

Answer:

Substrate:alkyl halide

Leaving group: Cl

Organic product: The nitrile

Inorganic product: Cl-

Nucleophile: CN-

Explanation:

An SN2 reaction is a concerted bimolecular reaction. Concerted means that it involves two reactions taking place at the same time while bimolecular means that the rate determining step involves two molecules. The cyanide ion attacks the alkyl halide from the rear. In the transition state, the leaving group (Cl-) is departing while the nucleophile (CN-) is forming a bond to the alkyl halide simultaneously. The alkyl halide is the substrate in the reaction. The organic product is the nitrile shown in the image attached.

3 0
3 years ago
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