Answer;
- This statement about matter and its behavior is best classified as a Law.
-It is the Law of Universal Gravitation.
Explanation;
-The Law of Universal Gravitation states that every point mass attracts every other point mass in the universe by a force pointing in a straight line between the centers-of-mass of both points, and this force is proportional to the masses of the objects and inversely proportional to their separation.This attractive force always points inward, from one point to the other.
-The Law applies to all objects with masses, big or small. Two big objects can be considered as point-like masses, if the distance between them is very large compared to their sizes or if they are spherically symmetric.
Answer:
a = 0,1[m/s^2]
Explanation:
First we need to indentify the initial data.
And using this kinematic equation we have:
![v = 4[m/s]\\v_{0}= 2 [m/s] \\t = 20[s]\\\\v= v_{0}+a*t\\a=\frac{v-v_{0}}{t} \\a= \frac{4-2}{20} \\a=0.1[m/s^{2}]](https://tex.z-dn.net/?f=v%20%3D%204%5Bm%2Fs%5D%5C%5Cv_%7B0%7D%3D%202%20%5Bm%2Fs%5D%20%5C%5Ct%20%3D%2020%5Bs%5D%5C%5C%5C%5Cv%3D%20v_%7B0%7D%2Ba%2At%5C%5Ca%3D%5Cfrac%7Bv-v_%7B0%7D%7D%7Bt%7D%20%5C%5Ca%3D%20%5Cfrac%7B4-2%7D%7B20%7D%20%5C%5Ca%3D0.1%5Bm%2Fs%5E%7B2%7D%5D)
We need to use the formula P = IV, where P is the power, I is the current and V is the voltage.
When we substitute our values in, we get:
100 = 240I, and so I = 0.42 Amps
Now, we have to work out the Resistance in the circuit at the operating temperature.
We do this using the formula V = IR
240 = (100/240) x R, and we get R = 576 Ohms
Since the resistance has gone up by a factor of 16, all we have to do now is to divide this answer by 16 to get the resistance at room temperature.
576/16 = 36 Ohms
Hope I helped!! xx
Answer:
soap will be dirty, maybe??
First, figure out what the angular speed of the merry-go-around is.
v ϖ = Using the formula for linear speed Since the angular speed is constant, there is no angular acceleration. Tangential acceleration is t a Radial acceleration is r a Thus the total acceleration is a = rω =1.2m×1.6rad / s =1.9m/ s = rα =1.2m×0rad / s2 = 0m/ s2 =rϖ2 =1.2m×(1.6rad / s)2 =3.1m/ s2 2 2 t r = a +a = 0+(3.1)2 =3.1m/ s2 1 4.0 rev
