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3 years ago

All matter on earth contains energy

Physics

2 answers:

exis [7]3 years ago

8 0

This is true since all matter contains some form of energy even just moving electrons and friction count as energy

Vikki [24]3 years ago

8 0

All matter and antimatter in the universe contains energy

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When jumping straight down, you can be seriously injured if you land stiff-legged. One way to avoid injury is to bend your knees

Naya [18.7K]

Answer:

a) F = 1.26 10⁵ N, b) F = 2.255 10³ N, c) F_ {soil} = 3078 N

Explanation:

For this exercise we will use the relationship between momentum and moment

I = Δp

F t = p_f -p₀

a) with stiff legs, final speed is zero, initial velocity is down

Ft = 0-p₀

F = m v / t

let's calculate

F = 84.0 6.82 / 4.56 10⁻³

F = 1.26 10⁵ N

b) bending the legs

let's calculate

F = 84.0 6.82 / 0.254

F = 2.255 10³ N

c) It is requested to calculate the force of the ground on the man

∑ F = F_soil -W

F_soil = F + W

F_ {soil} = 2.255 103 + 84 9.8

F_ {soil} = 3078 N

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3 years ago

A 60-kg person rides down an icy hill of 20° slope while standing on a 3.0-kg flat-bottomed bathroom scale. Assume there is no f

joja [24]

Answer: C) 0 N

Explanation:

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3 years ago

Two cars A and B are moving with velocities 20 m/s and 15 m/s in the direction east and west respectively. If

Sphinxa [80]

Answer:

Distance between them is 4,200 meters.

Explanation:

Consinder car A:

${ \bf{distance = speed \times time }}$

substitute:

$distance = 20 \times (2 \times 60) \\ = 2400 \: m$

Consider car B:

$distance = 15 \times (2 \times 60) \\ = 1800 \: m$

since these cars move in opposite directions, distance between them is their summation:

$distance \: between = { \sum(distance \: of \: each \: car)} \\ = 2400 + 1800 \\ = 4200 \: m$

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3 years ago

Which effects result from the influence of media and technology on children

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Can cause children into getting cyber bullying, being a thief, sexual behavior, anxiety, and depression

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4 years ago

A boat moves through the water with two forces acting on it. One is a 2000 N forward push by the water on the propeller, and the

jekas [21]

Answer:

a). a=0.2 $\frac{m}{s^{2} }$

b). x=10m

c). v=2 $\frac{m}{s}$

Explanation:

Force forward push = 2000N

Resistive force due water=1800N

Net force=2000N-1800N

Fn=200N

m=1000kg

t=10sec

a).

$F_{n} =m*a\\a=\frac{F_{n}}{m}\\ a=\frac{200N}{1000kg}\\ a=0.2 \frac{m}{s^{2} }$

b).

$x_{f}=x_{o}+ v_{o}*t+\frac{1}{2}*a*t^{2}\\x_{o}=0\\v_{o}=0\\x_{f}=\frac{1}{2}*a*t^{2}\\x_{f}=\frac{1}{2}*0.2*(10)^{2} \\x_{f}=10m$

c).

$v_{f}=v_{o}+a*t\\v_{o}=0\\v_{f}=a*t\\v_{f}=0.2\frac{m}{s^{2} }*10s\\v_{f}=2\frac{m}{s}$

3 0

3 years ago