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timurjin [86]
2 years ago
14

3. in adlerian therapy, clients learn how core beliefs that have been helpful in the past might not work well now and then to pu

t that understanding to use in the real world. what therapeutic process is referred to jim to overcome his core beliefs and move forward? as a counselor, how do you make him understand?
Physics
1 answer:
ipn [44]2 years ago
8 0

Adlerian therapy is a method in which a therapist collaborates with a client to pinpoint challenges and develop successful solutions for achieving their objectives.

Key Takeaways: Adlerian Therapy

Individual therapy, often known as Adlerian therapy, places an emphasis on the patient's capacity to effect good change in his or her own life.

Adlerian therapy consists of four stages: engagement, assessment, insight, and reorientation.

In Adler’s theory, individuals work to overcome feelings of inferiority and to act in ways that benefit the social interest.

Four Stages of Adlerian Therapy :

Engagement

Assessment

Insight

Reorientation

To learn more about Adlerian Therapy  refer : brainly.com/question/11722417

#SPJ4

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A- what constant acceleration, in SI units, must a car have to gofrom zero to 60 mph in 10 s?
umka2103 [35]

Answer:

(a) 0.017m/s^2

(b) 17/100,000

(c) 0.17m, 0.558ft

Explanation:

(a) speed = 60mph = 60m/1h × 1h/3600s = 0.017m/s, time = 10s

Acceleration (a) = speed ÷ time = 0.017m/s ÷ 10s = 0.0017m/s^2

(b) g = 9.8m/s^2, a = 0.0017m/s^2

a/g = 0.0017/9.8 = 0.00017 = 17/100,000

(c) Distance = speed × time = 0.017m/s × 10s = 0.17m

Distance in foot = 0.17 × 3.2808ft = 0.558ft

3 0
3 years ago
Read 2 more answers
Determine the thrust produced if 1.5 x 10^3 kg of gas exits the combustion chamber each second, with a speed of 4.00 x 10^3 m/s.
ozzi

Answer:

The thrust is 6\times 10^6\ N

Explanation:

Given that,

Mass of gas, m=1.5\times 10^3\ kg

The rate at which the gas is expelling, \dfrac{dv}{dt}=4\times 10^{3}\ m/s

We need to find the thrust produced by the gas.

We know that force is equal to the rate of change of momentum. So,

F=\dfrac{p}{t}

Also, p = mv

F=\dfrac{mv}{t}

So,

F=1.5\times 10^3\times 4\times 10^3\\\\F=6\times 10^6\ N

So, the thrust is 6\times 10^6\ N

3 0
4 years ago
Practice
marshall27 [118]

Answer:

In both cases the height is greater than 10.3 m

Explanation:

Pressure is defined by the relationship

       P = F / A

in this case the force is the weight of the two gases

       F = W = m g

If we use the definition of density

      ρ = m / V

      V = A h

      m = ρ A h

we substitute

       P = ρ g h

       h = \frac{P}{\rho g}

For this case the density of the gases is

       ρ' = 0.9 \rho_{water}

       h =\frac{P}{0.9 \ \rho_{water} g}

we calculate

     ρ’= 0.9 \rho_{water}

     h = 1 105 / (0.9 1000 9.8)

     h = 11.3 m

      ρ’= 0.8 \rho_{water}

       h = 1 105 / (0.8 1000 9.8

       h = 12.8 m

In both cases the height is greater than 10.3 m

4 0
3 years ago
Inside a 30.2 cm internal diameter stainless steel pan on a gas stove water is being boiled at 1 atm pressure. If the water leve
dybincka [34]

Answer:

Q = 20.22 x 10³ W = 20.22 KW

Explanation:

First we need to find the volume of water dropped.

Volume = V = πr²h

where,

r = radius of pan = 30.2 cm/2 = 15.1 cm = 0.151 m

h = height drop = 1.45 cm = 0.0145 m

Therefore,

V = π(0.151 m)²(0.0145 m)

V = 1.038 x 10⁻³ m³

Now, we find the mass of the water that is vaporized.

m = ρV

where,

m = mass = ?

ρ = density of water = 1000 kg/m³

Therefore,

m = (1000 kg/m³)(1.038 x 10⁻³ m³)

m = 1.038 kg

Now, we calculate the heat required to vaporize this amount of water.

q = mH

where,

H = Heat of vaporization of water = 22.6 x 10⁵ J/kg

Therefore,

q = (1.038 kg)(22.6 x 10⁵ J/kg)

q = 23.46 x 10⁵ J

Now, for the rate of heat transfer:

Rate of Heat Transfer = Q = q/t

where,

t = time = (18.6 min)(60 s/1 min) = 1116 s

Therefore,

Q = (23.46 x 10⁵ J)/1116 s

<u>Q = 20.22 x 10³ W = 20.22 KW</u>

8 0
3 years ago
A ball of mass 2.0 kg falls vertically and hits the ground with speed 7.0 ms-1 as shown below.
Sauron [17]

Answer:

8.0 Ns

Explanation:

Change in momentum is given as:

Final momentum - Initial momentum

= m*v - m*u

Where m = mass of ball

v = final velocity

u = initial velocity

Change in momentum = (2.0 * 3.0) - (2.0 * 7.0)

= 6.0 - 14.0 = -8.0 Ns

The magnitude will be |-8.0| = 8.0 Ns

7 0
4 years ago
Read 2 more answers
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