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weqwewe [10]
3 years ago
13

Two objects exert a gravitational force on 8N on one another what would that force be if the mass of both objects were doubled?

Physics
1 answer:
jolli1 [7]3 years ago
3 0
Gravitational force of attraction between two objects can be calculated from the following formula:
F = \frac{m_1 \cdot m_2}{r^{2}}
Where m with subscript stands for mass of the object and r is the distance between them.
When we double the mass of those two objects, distance between them stays the same, while in the numerator we have:
2\cdot m_1 \cdot 2 \cdot m_2 = 4\cdot m_1 \cdot m_2
When numerator in the second case 4 times greater than the 'original' numerator and denominator stays the same, force becomes 4 times greater.

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If a car can go from 0.0 to 60.0 mi/hr in 8.0 seconds, what would be its final speed after 5.0 seconds if its
o-na [289]
a =  \frac{60 }{8}  = 7,5 \ mph \ gained \ each\ second \\ final \ speed: 97.5 \ mph \ [ 50 + 7,5 * 5]
4 0
3 years ago
A certain superconducting magnet in the form of a solenoid of length 0.300 m can generate a magnetic field of 8.90 T in its core
Ivan

Answer:

The number of turns in the solenoid is 22366.

Explanation:

The number of turns in the solenoid can be found using the following equation:

B = \mu_{0} I\frac{N}{L}

Where:

B: is the magnetic field = 8.90 T

L: is the solenoid's length = 0.300 m

N: is the number of turns =?

I: is the current = 95 A

μ₀: is the magnetic constant = 4π×10⁻⁷ H/m

By solving equation (1) for N we have:

N = \frac{BL}{\mu_{0} I} = \frac{8.90 T*0.300 m}{4\pi \cdot 10^{-7} H/m*95 A} = 22366 turns

Therefore, the number of turns in the solenoid is 22366.

I hope it helps you!

8 0
3 years ago
The value found for the universal gravitational constant, G, will vary depending on the materials used for the balls of a Cavend
beks73 [17]
Higncfcn Senecavhehsnsbsgshnssm
8 0
3 years ago
7.5 h
Julli [10]

The distance traveled by plane flying at 1200 Km/h for 2.5 hours is 3000 Km.

Velocity is a vector quantity. It has both a direction and a magnitude. Speed is used to calculate the magnitude of velocity. The meter per second is the S.I. unit for this. The units km/h and km/s are additional units. [LT-1] is the dimensional equation for it.

The distance traveled by the object is calculated as the product of the velocity with which it was moving and the time interval for which the distance covered is calculated.

Distance traveled =  Velocity × Time

Given in the question

Velocity of the plane = 1200 Km/h

Time Traveled = 2.5 h

Put in the value, we get

Distance traveled =  1200 × 2.5

Distance traveled = 3000 Km

Hence, the distance traveled by plane flying at 1200 Km/h for 2.5 hours is 3000 Km.

LEARN MORE ABOUT VELOCITY HERE:

brainly.com/question/6504879

#SPJ9

7 0
2 years ago
g Two masses are involved in a collision on an axis (one dimensional). One mass is six times the mass of the second. Both masses
statuscvo [17]

Answer:

v₁f = 0.5714 m/s   (→)

v₂f = 2.5714 m/s   (→)

e = 1  

It was a perfectly elastic collision.

Explanation:

m₁ = m

m₂ = 6m₁ = 6m

v₁i = 4 m/s

v₂i = 2 m/s

v₁f = ((m₁ – m₂) / (m₁ + m₂)) v₁i +  ((2m₂) / (m₁ + m₂)) v₂i

v₁f = ((m – 6m) / (m + 6m)) * (4) +  ((2*6m) / (m + 6m)) * (2)  

v₁f = 0.5714 m/s   (→)

v₂f = ((2m₁) / (m₁ + m₂)) v₁i +  ((m₂ – m₁) / (m₁ + m₂)) v₂i

v₂f = ((2m) / (m + 6m)) * (4) + ((6m -m) / (m + 6m)) * (2)

v₂f = 2.5714 m/s   (→)

e = - (v₁f - v₂f) / (v₁i - v₂i)   ⇒   e = - (0.5714 - 2.5714) / (4 - 2) = 1  

It was a perfectly elastic collision.

8 0
3 years ago
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