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weqwewe [10]
3 years ago
13

Two objects exert a gravitational force on 8N on one another what would that force be if the mass of both objects were doubled?

Physics
1 answer:
jolli1 [7]3 years ago
3 0
Gravitational force of attraction between two objects can be calculated from the following formula:
F = \frac{m_1 \cdot m_2}{r^{2}}
Where m with subscript stands for mass of the object and r is the distance between them.
When we double the mass of those two objects, distance between them stays the same, while in the numerator we have:
2\cdot m_1 \cdot 2 \cdot m_2 = 4\cdot m_1 \cdot m_2
When numerator in the second case 4 times greater than the 'original' numerator and denominator stays the same, force becomes 4 times greater.

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A car has an engine which delivers a constant power. It accelerates from rest at time t = 0, and at t = t0 its acceleration is a
olga2289 [7]
Here is the answer of the given problem above.
Use this formula: <span>P = FV = ma*at = ma^2 t
</span><span>Substitute the values, and therefore, we got m(a0)^2t = m(x)^2 (2t)
then, solve for x which is the acceleration at 2t.
</span>The <span>answer would be a0/sqrt(2).
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7 0
3 years ago
Find the wavelength of the third line in the lyman series, and identify the type of em radiation.
Natalija [7]

The wavelength of the third line in the Lyman series, and identify the type of EM radiation

In this series, the spectral lines are obtained when an electron makes a transition from any high energy level (n=2,3,4,5... ). The wavelength of light emitted in this series lies in the ultraviolet region of the electromagnetic spectrum.

1 / lambda = R(h)* ( \frac{1}{(n1)^{2} } -   \frac{1}{(n2)^{2} })

                 = 109678 ( \frac{1}{1^{2} } -  \frac{1}{3^{2} } )

                 = 109678 (8/9)

   Lambda = 9 / (109678 * 8 )

                  = 102.6 * 10^{-9} m = 102.6 nm

To learn more about Lyman series here

brainly.com/question/5762197

#SPJ4

8 0
1 year ago
30.42
CaHeK987 [17]

Answer: Try C

Explanation:

It's the only one that makes since.

7 0
3 years ago
As part of an exercise program, a woman walks south at a speed of 2.00 m/s for 60.0 minutes. She then turns around and walks nor
Anastaziya [24]

Answer:

Option A

Solution:

As per the question:

The distance covered by the woman in the North direction, d = 3000 m

Time taken to travel in North direction, t = 25.0 min = 1500 s

Velocity of woman in the south direction, v = 2.00 m/s

Time taken in the south direction, t' = 60.0 min = 3600 s

Now,

The distance covered in the south direction, d' = vt' = 2.00\times 3600 = 7200\ m

Now, the total displacement is given by:

D = d' - d = 7200 - 3000 = 4200 m in South

(a) Average velocity of the woman in the whole journey is given by:

v_{avg} = \frac{Total\ displacement}{Total\ time} = \frac{4200}{t + t'}

v_{avg} = \frac{4200}{1500 + 3600} = 0.8235\ m/s ≈ 0.824 m/s South

6 0
3 years ago
PLEASE HELP ME<br> What is the net force acting on the car?
Hitman42 [59]
The net force acting on the car is 3 which slows the car down.
3 0
2 years ago
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