Answer:
In one liter of solution, there are 4.194 moles of H₃PO₄
Explanation:
A molal solution contains 1 mole of solute in 1 Kg of solvent.
A aqueous 5.257 molal solution of H₃PO₄ will contain 5.257 moles of H₃PO₄ in 1 Kg or 1000 g of water
.
Molar mass of H₃PO₄ = 98 g/mol
Therefore mass of H₃PO₄ = number of moles * molar mass
mass of H₃PO₄ = 5.257 mol * 98 g/mol = 515.2 g
mass of solution = mass of solute + mass of solvent
mass of solution = 515.2 + 1000 = 1515.2 g
Volume of solution = mass of solution / density of solution
Volume of solution = 1515.2 / 1.2089 = 1253.4 mL
Molarity of solution = number of moles / volume (L)
Molarity of solution = 5.257 / 1.2534 L = 4.194 mol/L
Therefore, in one liter of solution, there are 4.194 moles of H₃PO₄
It's 95 F
The formula is the following:
T
Because we are moving at a constant rate (seeing as we're on earth and the earth is spinning) but the moon does not spin as it revolves around us, therefore we only see the one side of it.
Answer:
Density of copper = 8.9 g/cm³
The density of liquid mercury is 13.6 g/cm³ which means mercury is denser than copper so copper will float on liquid mercury.
Explanation:
Given data:
weight of copper metal = 1896 g
Dimensions of block = 8.4 cm, 5.5 cm, 4.6 cm
Density of copper = ?
Will it float to the liquid mercury = ?
Solution:
Density:
Density is equal to the mass of substance divided by its volume.
Units:
SI unit of density is Kg/m3.
Other units are given below,
g/cm3, g/mL , kg/L
Formula:
D=m/v
D= density
m=mass
V=volume
volume of coper metal = 8.4 cm × 5.5 cm × 4.6 cm
volume of coper metal =212.52 cm³
d = 1896 g/ 212.52 cm³
d = 8.9 g/cm³
The density of liquid mercury is 13.6 g/cm³ which means mercury is denser than copper so copper will float on liquid mercury.
Since 1 mol --> 6.023x10^23 number of atoms/particles/molecules
Then do
1 : 6.023x10^23
6.72 : X
X= 6.72 x 6.023x10^23
X= 4.047x10^24 number of molecules
