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serious [3.7K]
3 years ago
7

According to Kepler's third law (p2 = a3), how does a planet's mass affect its orbit around the Sun? Group of answer choices

Physics
1 answer:
anyanavicka [17]3 years ago
3 0

Answer:

A planet's mass has no effect on its orbit around the Sun.

Explanation:

The kepler's third law tells us:

p^2=a^3

where p is the orbit period and a is the semi-major axis.

As we can see from the equation, the period depends only on the measure of the semi-major axis a of the orbit, that is, how far a planet is from the sun.

The equation tells us that the closer a planet is to the sun, the faster it will go around it.

The mass does not appear in the equation to calculate the period.

This is why it is concluded from the third law of Kepler that<u> the period, or the orbit of a planet around the sun, does not depend on its mass.</u>

the answer i: A planet's mass has no effect on its orbit around the Sun.

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A particle moves at a constant speed in a circular path with a radius of r=2.06 cm. If the particle makes four revolutions each
nataly862011 [7]

The centripetal acceleration is 13.0 m/s^2

Explanation:

For an object in uniform circular motion, the centripetal acceleration is given by

a=\frac{v^2}{r}

where

v is the speed of the object

r is the radius of the circle

The speed of the object is equal to the ratio between the length of the circumference (2\pi r) and the period of revolution (T), so it can be rewritten as

v=\frac{2\pi r}{T}

Therefore we can rewrite the acceleration as

a=\frac{4\pi^2 r}{T^2}

For the particle in this problem,

r = 2.06 cm = 0.0206 m

While it makes 4 revolutions each second, so the period is

T=\frac{1}{4}s = 0.25 s

Substituting into the equation, we find the acceleration:

a=\frac{4\pi^2 (0.0206)}{0.25^2}=13.0 m/s^2

Learn more about centripetal acceleration:

brainly.com/question/2562955

#LearnwithBrainly

8 0
3 years ago
What is (Fnet3)x, the x-component of the net force exerted by these two charges on a third charge q3
Pachacha [2.7K]

This question is incomplete, the complete question is;

Coulomb's law for the magnitude of the force F between two particles with charges Q and Q' separated by a distance d is

|FI = |QQ'I / d²

where K = 1/4π∈0, and

∈0 = 8.854 × 10⁻¹² C²/(N.m²) is the permittivity of free space.

Consider two point charges located on the x-axis:

one charge, q₁ = -18.5 nC, is located at

x₁ = -1.715m; the charge q₂ = 30.5 nC, is at the origin ( x₂=0 )

What is (Fnet3)x, the x-component of the net force exerted by these two charges on a third charge q₃ = 51.0 nC placed between q₁ and q₂ at x₃ = -1.085 m ?

Answer: (Fnet3)x = -3.3287 × 10⁻⁵ N

Explanation:

Given that;

Q₁ = -18.5 nC       Q₃ = 51 nC        Q₂ = 30.5 nC

x₁ = - 1.715m         x₃ = - 1.085m     x₂ = 0

Now

x - component of Net force on charge Q₃ is

(Fnet3)x = -K|Q₁I|Q₃I / r₁3² - -K|Q₂I|Q₃I / r₂3²

(Fnet3)x = -(9×10⁹)(51×10⁻⁹) [ 18.5 / ((-1.085 + 1.715)²) + (30.5 / (-1.085)² ] × 10⁻⁹

(Fnet3)x = -3.3287 × 10⁻⁵ N

6 0
3 years ago
15. यदि दिइएको केन्द्र 0 भएको वृत्तको
miv72 [106K]

Answer:

what language is that

Explanation:

i don't understand the languge u used please can you change it

8 0
2 years ago
Is a projectile motion graph a straight graph or a curved graph<br>​
Usimov [2.4K]

Answer:

» Projectile motion is a curved graph.

☑ This is because projectile motion consists of both vertical and horizontal motion, with one starting angle. Hence as the body starts motion, it is acted upon by gravity.

At point v = 0, the motion is free from gravity hence approaching horizontal motion.

Examples;

  • A ball kicked upwards at an angle which is not 90°
  • A man playing golf.
  • A plane dropping a bomb.

7 0
2 years ago
Read 2 more answers
A 512Hz tuning fork is used with a resonating column to determine the velocity of sound in water. If the spacing between resonan
EastWind [94]

Answer:

v= 1495.04 m/s

Explanation:

The formula for velocity of sound is given by ;

v= fλ   --------where

v= velocity of sound

f= frequency of turning fork

λ = wavelength

However,

Δ L = 1/2 λ   ------where Δ L is spacing between resonances.

1.46 = 1/2 λ

1.46 * 2 = λ

2.92 m = λ

v= fλ

v= 512 * 2.92

v= 1495.04 m/s

6 0
3 years ago
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