According to Kepler's third law (p2 = a3), how does a planet's mass affect its orbit around the Sun? Group of answer choices
1 answer:
Answer:
A planet's mass has no effect on its orbit around the Sun.
Explanation:
The kepler's third law tells us:
where is the orbit period and
is the semi-major axis.
As we can see from the equation, the period depends only on the measure of the semi-major axis of the orbit, that is, how far a planet is from the sun.
The equation tells us that the closer a planet is to the sun, the faster it will go around it.
The mass does not appear in the equation to calculate the period.
This is why it is concluded from the third law of Kepler that<u> the period, or the orbit of a planet around the sun, does not depend on its mass.</u>
the answer i: A planet's mass has no effect on its orbit around the Sun.
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Complete Question:
In the same configuration of the previous problem 3, four long straight wires are perpendicular to the page, and their cross sections form a square of edge length a = 13.5 cm. Each wire carries 7.50 A, and the currents are out of the page in wires 1 and 4 and into the page in wires 2 and 3.
a) Draw a diagram in a (x,y) plane of the four wires with wire 4 perpendicular to the origin. Indicate the current's directions.
b) Draw a diagram of all magnetic fields produced at the position of wire 3 by the other three currents.
c) Draw a diagram of all magnetic forces produced at the position of wire 3 by the other three currents.
d) What are magnitude and direction of the net magnetic force per meter of wire length on wire 3?
Answer:
force, 1.318 ₓ 10⁻⁴
direction, 18.435°
Explanation:
The attached file gives a breakdown step by step solution to the questions
A system of equations is a group of equations with the same variables that we need to solve simultaneously. Such that the solutions is given by the intersection betweens graphs of the functions.
We will see that the solution is (16.4, 807.0)
Here the system is:
To solve a system we usually need to isolate one of the variables in one equation and replace that in the other equation, here we already see that we have x isolated in the two equations, so we can write:
Now we can solve the above equation for t:
This is just a quadratic equation, the solution is given by the Bhaskara's formula, we will get:
Then the two values of t are:
t = (45.0 + 53.4)/6 = 16.4
t = (45.0 - 53.4)/6 = -1.4
We want the positive solution, so we choose t = 16.4
To complete the solution we need to evaluate one of our functions in this time. Let's use the first one:
x = 45.0*16.4 + 69.0 = 807.0
Then the solution is:
(16.4, 807.0)
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