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2 years ago

According to Kepler's third law (p2 = a3), how does a planet's mass affect its orbit around the Sun? Group of answer choices

Physics

1 answer:

anyanavicka [17]2 years ago

3 0

Answer:

A planet's mass has no effect on its orbit around the Sun.

Explanation:

The kepler's third law tells us:

$p^2=a^3$

where $p$ is the orbit period and $a$ is the semi-major axis.

As we can see from the equation, the period depends only on the measure of the semi-major axis $a$ of the orbit, that is, how far a planet is from the sun.

The equation tells us that the closer a planet is to the sun, the faster it will go around it.

The mass does not appear in the equation to calculate the period.

This is why it is concluded from the third law of Kepler that<u> the period, or the orbit of a planet around the sun, does not depend on its mass.</u>

the answer i: A planet's mass has no effect on its orbit around the Sun.

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Answer:

M = 0.730*m

V = 0.663*v

Explanation:

Data Given:

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Conservation of Momentum:

$P_{initial} = P_{final}\\m*v_{i} = m*0.516v_{i} + M*V\\0.484m*v_{i} = M*V .... Eq1$

Energy Balance:

$\frac{1}{2}*m*v^2_{i} = \frac{1}{2}*m*(0.516v_{i})^2 + \frac{1}{2}*M*V^2 + 0.413*\frac{1}{2}*m*v^2_{i}\\\\0.320744*m*v^2_{i} = M*V^2\\\\M = \frac{0.320744*m*v^2_{i} }{V^2} ....... Eq 2$

Substitute Eq 2 into Eq 1

$0.484*m*v_{i} = \frac{0.320744*m*v^2_{i} }{V^2} *V \\0.484 = 0.320744*\frac{v_{i} }{V} \\\\V = 0.663*v_{i}$

Using Eq 1

$0.484m*v_{i} = M* 0.663v_{i}\\\\M = 0.730*m$

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3 years ago

The planet Jupiter has an acceleration due to gravity that is approximately 2.4 times as much as the earth (23.2 m s2 ). Which o

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On Jupiter, C. your weight would increase by a factor of 2.4 . Weight is a product of mass and gravity. Mass does not change dependent upon location.

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Answer:

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3 years ago

At what time of year is the intensity of solar radiation striking each of earth's hemispheres weakest?

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3 years ago

A rigid tank contains nitrogen gas at 227 °C and 100 kPa gage. The gas is heated until the gage pressure reads 250 kPa. If the a

aleksley [76]

Answer:

T₂ =602 °C

Explanation:

Given that

T₁ = 227°C =227+273 K

T₁ =500 k

Gauge pressure at condition 1 given = 100 KPa

The absolute pressure at condition 1 will be

P₁ = 100 + 100 KPa

P₁ =200 KPa

Gauge pressure at condition 2 given = 250 KPa

The absolute pressure at condition 2 will be

P₂ = 250 + 100 KPa

P₂ =350 KPa

The temperature at condition 2 = T₂

We know that

$\dfrac{T_2}{T_1}=\dfrac{P_2}{P_1}\\T_2=T_1\times \dfrac{P_2}{P_1}\\T_2=500\times \dfrac{350}{200}\ K\\$

T₂ = 875 K

T₂ =875- 273 °C

T₂ =602 °C

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3 years ago