A compressed spring has 16.2j of elastic potential energy when it is compressed 0.30m what is the spring constant of the spring

Elena earns $10.50 per hour as a server working x hours per week. She also earns $8.50 per hour editing poetry for y hours per w

klasskru [66]

Answer:

Option A: Elena can work as a server for 5 hours and edit poetry for 10 hours.

Explanation:

We are given the system of linear inequalities modeling this situation as; 10.50x + 8.50y ≥ 125

x + y ≤ 17

Where;

x represents number of server working hours per week.

y represents number of editing poetry hours per week.

In option A, x = 5 and y = 10. Let's plug them both into the first equation;

10.50(5) + 8.50(10) ≥ 125

Left hand side gives 137.5. So it fulfills the inequality.

Repeating the same for the 2nd equation, we have;

5 + 10 ≤ 17

Left hand side is 15 and it fulfills the equation. Option A is correct.

In option B, x = 10 and y = 9. Let's plug them both into the first equation;

10.50(10) + 8.50(9) ≥ 125

Left hand side gives 181.5. So it fulfills the inequality.

Repeating the same for the 2nd equation, we have;

10 + 9 ≤ 17

Left hand side is 17 and it doesn't fulfill the inequality. Option B is wrong.

In option C, x = 10 and y = 1. Let's plug them both into the first equation;

10.50(10) + 8.50(1) ≥ 125

Left hand side gives 113.5. So it doesn't fulfill the inequality.

Option C is wrong.

In option D, x = 3 and y = 10. Let's plug them both into the first equation;

10.50(3) + 8.50(10) ≥ 125

Left hand side gives 116.5. So it doesn't fulfill the inequality.

Option D is wrong.

5 0

3 years ago

Light with a wavelength of 5.0 · 10-7 m strikes a surface that requires 2.0 ev to eject an electron. Calculate the energy, in jo

GenaCL600 [577]

6.2 x 10^-13 is your answer

7 0

4 years ago

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A transverse mechanical wave is traveling along a string lying along the x-axis. The displacement of the string as a function of

kvv77 [185]

The wavelength of the wave is 1.16m and the velocity is 23.64m/s.

To find the answer, we have to know more about the Transverse waves.

<h3>How to find different parameters of a wave?</h3>

The displacement of the string as a function of position and time, y(x,t), when the wave traveling along a string lying along the x-axis is given as,

$y(x,t)=0.048sin(5.40x-128t)$

Comparing this with the general form of wave equation, we get,

$amplitude, a=0.048m\\wave vector, k=5.40\\angular frequency,w=128Hz$

We have to find the wavelength of the wave, for this, we have the expression as,

$k=\frac{2\pi }{wavelength} \\\\wavelength=\frac{2\pi }{k} =\frac{2*3.14}{5.40} \\\\wavelength=1.16m$

We have to find the velocity of the wave,

$v=frequency*wavelength\\2\pi f=w, thus,\\f=\frac{w}{2\pi } =\frac{128}{2*3.14}=20.38s^{-1}\\\\v=1.16*20.38=23.64m/s$

Thus, we can conclude that, the wavelength of the wave is 1.16m and the velocity is 23.64m/s

Learn more about the transvers waves here:

brainly.com/question/25746208

#SPJ1

5 0

1 year ago

A slingshot is used to launch a stone horizontally from the top of a 20.0 meter cliff. The stone lands 36.0 meters away.

alisha [4.7K]

A)

It is a launch oblique, therefore the initial velocity in the vertical direction is zero. Space Hourly Equation in vertical, we have:

$S=S_{o}+v_{o}t+ \frac{at^2}{2} \\ 20= \frac{10t^2}{2} \\ t=2s$

Through Definition of Velocity, comes:

$\Delta v= \frac{\Delta S}{\Delta t} \\ v_x= \frac{36}{2} \\ \boxed {v_{x}=18m/s}$

B)

Using the Velocity Hourly Equation in vertical direction, we have:

$v_{y}=v_{y_{o}}+gt \\ v_{y}=10\times2 \\ \boxed {v_{y}=20m/s}$

The angle of impact is given by:

$cos(\theta) =\frac{v_{x}}{v_{y}} \\ cos(\theta) = \frac{18}{20} \\ cos(\theta) =0.9 \\ arccos(0.9)=\theta \\ \boxed {\theta \approx 25.84}$

If you notice any mistake in my english, please let me know, because i am not native.

7 0

3 years ago

Read 2 more answers

How much energy from the sun actually reaches the corn answer?

Serhud [2]

The energy from the sun that reaches the corn is about two billionths.

3 0

3 years ago

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