Ah hah ! We can do this the easy way, or we can do it the hard way.
Whereas, in honor of, and pursuant to my natural laziness, I'm going to
do it the easy way, and not even talk about the hard way. Please fasten
your seat belt. It may be a boompy ride.
There are a few different ways to calculate the CHANGE in
an object's momentum. For this particular problem, it's
best to use this equation for "Change in momentum":
CHANGE in momentum = IMPULSE delivered to the object.
Do you remember how to calculate impulse ?
Impulse = (force exerted in the object) x (time the force lasts)
-- In the question, it says that the same force is exerted on each car,
and they all get it for 10 seconds apiece.
-- Since the force is the same on each car, and the force lasts for
the same amount of time on each car, the IMPULSE delivered to
each car is the same !
-- So the CHANGE IN MOMENTUM is the same for each car.
-- They all started out from 'rest', so each one started with zero momentum.
-- The CHANGE IN MOMENTUM is the same for each car.
-- So at the end of 10 seconds, NO CAR has the 'most momentum'.
All three cars have the SAME momentum.
Do you see why I said that this is the 'easy way' to solve it ?
If the mass of one of the objects is tripled, then the force of gravity between them is tripled. ... Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces.
Answer: oh my. I just had the answer in my head but its gone now
Explanation: