Question

Consider being at the top of cliff and throwing a book off the ledge. The book leaves at an angle of 52 degrees and a velocity of 16.0 m/s. If it moves through the air for 13.4 seconds, how far does it fall

Answer 1

The vertical distance through which the book falls is determined as 1,048.8 m.

Height of the book fall

The vertical distance through which the book falls is calculated as follows;

h = vt + ¹/₂gt²

where;

• h is height of fall
• v is initial vertical velocity
• g is acceleration due to gravity

h = (16 x sin52)(13.4)  + (0.5)(9.8)(13.4²)

h = 1,048.8 m

Thus, the vertical distance through which the book falls is determined as 1,048.8 m.

Learn more about height of fall here:  brainly.com/question/15611384

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