(Giving 75 points, Please do not answer if you do not know. Wrong answers will result in me reporting them.)
2 answers:
Answer:
OQ = 11
Step-by-step explanation:
<u>Segment Addition Postulate</u>
If a third point B lies on a line segment with endpoints A and C, then AB + BC = AC
Given:
- OP = 17
- QP = 6
Q is the point on the line segment OP, so:
⇒ OQ + QP = OP
Substitute the given values of OP and QP to find OQ:
⇒ OQ + 6 = 17
⇒ OQ + 6 - 6 = 17 - 6
⇒ OQ = 11
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The system of linear inequalities x + 10y ≤ 80, x ≥ 30 and y ≤ 4 is represented in a graph below
<h3>Graph of Linear Inequality</h3>The graph of an inequality in two variables is the set of points that represents all solutions to the inequality. A linear inequality divides the coordinate plane into two halves by a boundary line where one half represents the solutions of the inequality.
To solve this problem, we would require the use of graph which can easily be done with a graphing calculator.
x + 10y ≤ 80
x ≥ 30
y ≤ 4
The graph of the inequalities is attached below
Learn more on graph of linear inequality here;
#SPJ1
2 ways: Easy and hard
Hard=A
Easy=B
A: 1/2x+4 work from there so we do fun stuff with it make something that can be simplified so 1/2x+4 times (2/2)=x+8 now square the whole thing and put the result in a square root thingie (x+8)^2=x^2+16x+64
multiply the whole thing by 4/4 and put ![\sqrt{16} [\tex] on top so then [tex] \sqrt{x^2+16x+64}](https://tex.z-dn.net/?f=%20%5Csqrt%7B16%7D%20%5B%5Ctex%5D%20on%20top%20so%20then%20%0A%5Btex%5D%20%5Csqrt%7Bx%5E2%2B16x%2B64%7D%20)
times 
=
=
to solve it, factor out the 16 in the square root and then square root 16 to get 4
then it will be (4 times square root of equation)/4=square root of equatio
factor square root of equation and square root it and get x+8
divide by 2 to get 1/2x+4
B: 1/2x+4
put stuff that cancels out
1/2x+3x-3x+4+56-56
move them around
3 and 1/2x-3x+60-56
or
2x-3x+1 and 1/2x+30-20+30-36
then just add like terms to solve
Hard=A
Easy=B
A: 1/2x+4 work from there so we do fun stuff with it make something that can be simplified so 1/2x+4 times (2/2)=x+8 now square the whole thing and put the result in a square root thingie (x+8)^2=x^2+16x+64
B: 1/2x+4
put stuff that cancels out
1/2x+3x-3x+4+56-56
move them around
3 and 1/2x-3x+60-56
or
2x-3x+1 and 1/2x+30-20+30-36
then just add like terms to solve