(Giving 75 points, Please do not answer if you do not know. Wrong answers will result in me reporting them.)
2 answers:
Answer:
OQ = 11
Step-by-step explanation:
<u>Segment Addition Postulate</u>
If a third point B lies on a line segment with endpoints A and C, then AB + BC = AC
Given:
- OP = 17
- QP = 6
Q is the point on the line segment OP, so:
⇒ OQ + QP = OP
Substitute the given values of OP and QP to find OQ:
⇒ OQ + 6 = 17
⇒ OQ + 6 - 6 = 17 - 6
⇒ OQ = 11
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The graph is attached.
We first graph the point where his catch reached the surface, (35, 0). Since it travels upward at a constant rate, the graph will be linear. We also need to know where it starts (what depth it is at when he begins reeling it in). We can use the formula d=rt as a template for our function. d would be distance (in our case, depth), r is the rate (speed) and t is the amount of time.
To find how far the catch had to travel to reach the surface, we set up our equation as:
d = 0.1(35)
This will tell us how much distance it traveled in 35 seconds. 0.1(35)=3.5, so the catch started 3.5m under water. It then travels up at 0.1 m per second.
We first graph the point where his catch reached the surface, (35, 0). Since it travels upward at a constant rate, the graph will be linear. We also need to know where it starts (what depth it is at when he begins reeling it in). We can use the formula d=rt as a template for our function. d would be distance (in our case, depth), r is the rate (speed) and t is the amount of time.
To find how far the catch had to travel to reach the surface, we set up our equation as:
d = 0.1(35)
This will tell us how much distance it traveled in 35 seconds. 0.1(35)=3.5, so the catch started 3.5m under water. It then travels up at 0.1 m per second.