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Assoli18 [71]
3 years ago
14

3. 200 ml of 0.2 M HCl is neutralized with 0.1 M

Chemistry
1 answer:
algol [13]3 years ago
3 0

Answer:

  • <u><em>a. 0.1 M</em></u>

Explanation:

By definition, <em>half neutralization</em> is the point at which half of the acid has been neutralized.

The neutralization reaction that you are studying is the acid-base reaction:

  • HCl (aq) + NaOH (aq) → NaCl(aq) + H₂O (aq)

Then, since the starting molarity of the acid (HCl) is 0.2 M, you just need to find half of that concentration:

  • Half molarity = M / 2 = 0.2 M / 2 = 0.1 M

So, the answer is the first choice: a. 0.1 M.

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1. A gas has a volume of 140L at 37 ºC and 620 kpa pressure. Calculate its volume at STP.
solniwko [45]

Answer:

1. Volume as STP = 755 L

2. Outside temperature = 255 K

3. Percentage yield = 70.5%

Explanation:

1. At STP, pressure  = 101.3 kpa, temperature  = 0°C or 273.15 K

Using the general gas equation :

P1V1/T1 = P2V2/T2

P1 = 620 kpa

V1 = 140 L

T1 = 37°C or (273.15 + 37) K = 310.15 K

P2 = 101.3 kpa

V2 = ?

T2 = 273.15 K

V2 = P1V1T2/P2T1

V2 = 620 × 140 × 273.15 / 101.3 × 310.15

V2 = 755 L

2. Using Charles' gas law:

V1/T1 = V2/T2

V1 = 2.5 L

T1 = 290 K

V2 = 2.2 L

T2 = ?

T2 = V2T1/VI

T2 = 2.2 × 290 / 2.5

T2 = 255 K

3. Equation of reaction : 2 Al + 3 CuSO4 ---> Al2 (SO4)3 + 3 Cu

From equation of the reaction,  2 moles of Al produces 3 moles of Cu

Molar mass of Al = 27 g; Molar mass of Cu = 63.5 g

2 moles of Al = 2 × 27 g = 54 g; 3 moles of Cu = 3× 63.5 = 190.5 g

54 g of Al produces 190.5 g of Cu

1.87 g of Al will produce 190.5/54 × 1.87 g of Cu = 6.60 g of Cu

Percentage yield = actual yield /theoretical yield × 100%

Percentage yield = 4.65/6.60 × 100%

Percentage yield = 70.5%

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2 years ago
Geologically, the Himalayan mountain range is one of the youngest mountain ranges on Earth. It has nine of the ten highest peaks
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Answer:

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what noble gas has the same electron configuration as each of the ions in the following compounds? a. Cesium sulfide b. strontiu
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Answer:

A. Cesium sulfide

Explanation:

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Balance the following redox reaction if it occurs in acidic solution. What are the coefficients in front of h2c2o4 and h2o in th
postnew [5]

The balanced redox reaction, if it occurs in acidic solution, is

5C₂O₄²⁻(aq) + 2MnO₄⁻(aq) + 16H⁺-----> 10CO₂(g) + 2Mn²⁺(aq) + 8H₂O(l)

<h3>What are redox reaction?</h3>

Redox reactions are those in which loss and again of electrons occur.

To balance the redox reaction, we must first break the whole reaction into half equations;

Oxidation half equation

\rm 5C_2O4^2^-(aq) + 10e + 8H^+----- > 10CO_2(g) + 4H_2O(l)

Reduction half equation

\rm 2MnO_4^- (aq) + 10e + 8H^+----- > 2Mn^2+(aq) + 4H_2O(l)

Now combine both the reactions

\rm 5C_2O_4^2-(aq) + 2MnO4^- (aq) + 16H^+----- > 10CO_2(g) + 2Mn^2+(aq) + 8H_2O(l)

Thus, the coefficient of H₂C₂O₄ is 5 and that of water is 8.

Learn more about redox reactions

brainly.com/question/13293425

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What is the coordination number of an iridium atom in the face-centered cubic structure of iridium?
liubo4ka [24]

Answer:12

Explanation:

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3 years ago
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