3. 200 ml of 0.2 M HCl is neutralized with 0.1 M
1 answer:
Answer:
Explanation:
By definition, <em>half neutralization </em> is the point at which half of the acid has been neutralized.
The neutralization reaction that you are studying is the acid-base reaction:
HCl (aq) + NaOH (aq) → NaCl(aq) + H₂O (aq)
Then, since the starting molarity of the acid (HCl) is 0.2 M, you just need to find half of that concentration:
Half molarity = M / 2 = 0.2 M / 2 = 0.1 M
So, the answer is the first choice: a. 0.1 M.
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