Answer:
+1.03 V
Explanation:
The standard emf of the voltaic cell is the value of the standard potential of it, which is calculated by the standard reduction potential (E°).
The standard reduction potential is the potential needed for the reduction reaction happen, and it's determined by the reaction with the hydrogen cell (which has E° = 0.0V). The half-reactions of reduction of Ni⁺² and Ag⁺, are:
Ni⁺²(aq) + 2e⁻ → Ni(s) E° = -0.23 V
Ag⁺(aq) + e⁻ → Ag(s) E° = +0.80 V
The value is calculated by a spontaneous reaction, in which the cell with the greater E° is reduced (gain electrons), and the other is oxidized (loses electrons). So, Ag⁺ reduces.
emf = E°reduces - E°oxides
emf = 0.80 - (-0.23)
emf = +1.03 V
Answer:
A
Explanation:
it's the sum of the masses of all the atoms in the molecule
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Answer:
Silver has to give up one electron.
Explanation:
Silver is a transition element and has a partially filled 4d- orbital having 9 electrons and a 5s orbital having 2 electrons in it. In order to achieve stability, silver must have completely filled d-orbital having a maximum number of 10 electrons in it.
Therefore, one electron from 5s orbital jumps to 4d orbital to make it stable. Now, 5s orbital has only one electron, and it will be easy for silver to lose this electron to attain a stable electronic configuration.
Answer:
Molecules in the gas move faster due to the fact they have more energy
Explanation:
If you put more heat the higher the volume will be. Less heat means less volume.
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Answer:
1) P₄ + 5O₂ → P₄O₁₀ redox reaction
2) P₄O₁₀ + 6H₂O → 4H₃PO₄ acid-base reaction
3) Ca₅(PO₄)₃F + 5H₂SO₄ → 3H₃PO₄ + HF + 5CaSO₄ precipitation reaction
Explanation:
The reactions that take place in the <u>electric furnace method</u> are:
1) P₄ + 5O₂ → P₄O₁₀
This is a redox reaction, because the oxidation state of the reactants is changed.
2) P₄O₁₀ + 6H₂O → 4H₃PO₄
This is an acid-base reaction, because there's an exchange of H⁺ species.
The reaction that takes place in the <u>wet process</u> is:
3) Ca₅(PO₄)₃F + 5H₂SO₄ → 3H₃PO₄ + HF + 5CaSO₄
This is an precipitation reaction, because a precipitate (a solid phase in a liquid phase) is formed.
