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Assoli18 [71]
3 years ago
14

3. 200 ml of 0.2 M HCl is neutralized with 0.1 M

Chemistry
1 answer:
algol [13]3 years ago
3 0

Answer:

  • <u><em>a. 0.1 M</em></u>

Explanation:

By definition, <em>half neutralization</em> is the point at which half of the acid has been neutralized.

The neutralization reaction that you are studying is the acid-base reaction:

  • HCl (aq) + NaOH (aq) → NaCl(aq) + H₂O (aq)

Then, since the starting molarity of the acid (HCl) is 0.2 M, you just need to find half of that concentration:

  • Half molarity = M / 2 = 0.2 M / 2 = 0.1 M

So, the answer is the first choice: a. 0.1 M.

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Addition of an excess of lead (II) nitrate to a 50.0mL solution of magnesium chloride caused a formation of 7.35g of lead (II) c
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Answer:

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This is a solubility equilibrium, where you have a precipitate formed, lead(II) chloride. This salt can be dissociated as:

           PbCl₂(s)  ⇄  Pb²⁺ (aq)  +  2Cl⁻ (aq)     Kps

Initial        x

React       s

Eq          x - s              s                  2s

As this is an equilibrium, the Kps works as the constant (Solubility product):

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3 0
3 years ago
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