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Answer:</h3>
Mike is involved in developing the model building codes that various states and local authorities in the United States adopt. He works with the <u>Workers</u> , which consists of members who are building code officials and building safety professionals.
Answer:
Atlantis benefited from lessons learned in the construction and testing of Enterprise, Columbia and Challenger. ... The Experience gained during the Orbiter assembly process also enabled Atlantis to be completed with a 49.5 percent reduction in man hours (compared to Columbia).
Explanation:
Answer:
See explaination
Explanation:
Please kindly check attachment for the step by step solution of the given problem.
Answer:
Yes, fracture will occur
Explanation:
Half length of internal crack will be 4mm/2=2mm=0.002m
To find the dimensionless parameter, we use critical stress crack propagation equation
and making Y the subject
![Y=\frac {K}{\sigma_c \sqrt {a\pi}}](https://tex.z-dn.net/?f=Y%3D%5Cfrac%20%7BK%7D%7B%5Csigma_c%20%5Csqrt%20%7Ba%5Cpi%7D%7D)
Where Y is the dimensionless parameter, a is half length of crack, K is plane strain fracture toughness,
is critical stress required for initiating crack propagation. Substituting the figures given in question we obtain
![Y=\frac {K}{\sigma_c \sqrt {a\pi}}= \frac {40}{300\sqrt {(0.002*\pi)}}=1.682](https://tex.z-dn.net/?f=Y%3D%5Cfrac%20%7BK%7D%7B%5Csigma_c%20%5Csqrt%20%7Ba%5Cpi%7D%7D%3D%20%5Cfrac%20%7B40%7D%7B300%5Csqrt%20%7B%280.002%2A%5Cpi%29%7D%7D%3D1.682)
When the maximum internal crack length is 6mm, half the length of internal crack is 6mm/2=3mm=0.003m
and making K the subject
and substituting 260 MPa for
while a is taken as 0.003m and Y is already known
![K=260*1.682*\sqrt {0.003*\pi}=42.455 Mpa](https://tex.z-dn.net/?f=K%3D260%2A1.682%2A%5Csqrt%20%7B0.003%2A%5Cpi%7D%3D42.455%20Mpa)
Therefore, fracture toughness at critical stress when maximum internal crack is 6mm is 42.455 Mpa and since it’s greater than 40 Mpa, fracture occurs to the material