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ziro4ka [17]
3 years ago
11

Which of these statements about the conservation of mass is not correct?

Chemistry
1 answer:
Verdich [7]3 years ago
5 0
B
That’s the real answer
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68 POINTS WILL GIVE BRAINliest!!!
AleksandrR [38]

Answer:

D

C

Explanation:

4 0
3 years ago
Read 2 more answers
You find a compound composed only of element X and chlorine and you know that the compound is 13.10% X by mass. Each molecule of
8_murik_8 [283]

Answer:

Explanation:

So, the formula for the compound should be:

XCl_{6}

Now we assume that we have 1 mol of substance, so we can make calculations to know the molar mass of element X, as follows:

M_{Cl}=35.45g/mol\\

So we have that 6 moles weight 212.7g, and we can make a rule of three to know the weight of compound X:

212.7g\rightarrow 86.9\%\\x\rightarrow 13.1\%\\\\x=\frac{212.7g*13.1}{86.9} =32.06g

As we used 1 mol, we know that the molar mass is 32.06g/mol

So the element has a molar mass of 32.06 g/mol and an oxidation state of +6, with this information, we can assure that the element X is sulfur, so the compound is SCl_{6}

8 0
3 years ago
I need help ASAP! How many reactants and products are in each element according to the chemical equation above.
Len [333]

Answer:

O 4

C 1

1 sodium

3 H

Products

1 sodium

3 H

4 O

1 C

Explanation:

7 0
3 years ago
If 0.0714 moles of N2 gas occupies 1.25 L space, how many moles of N2 have a volume of 25.0 L? Assume temperature and pressure s
vfiekz [6]

Answer:

1.428 moles

Explanation:

If 0.0714 moles of N2 gas occupies 1.25 L space,

how many moles of N2 have a volume of 25.0 L?

Assume temperature and pressure stayed constant.

we experience it 0.0714 moles: 1.25L space

x moles : 25L of space

to get the x moles, cross multiply

(0.0714 x 25)/1.25

1.785/1.25 = 1.428 moles

8 0
3 years ago
Nitrogen dioxide decomposes to nitric oxide and oxygen via the reaction: 2NO2 → 2NO + O2 In a particular experiment at 300 °C, [
Setler [38]

Answer:

rate=-1.75x10^{-5}\frac{M}{s}

Explanation:

Hello,

In this case, for the given information, we can compute the rate of disappearance of NO₂ by using the following rate relationship:

rate=\frac{1}{2}*\frac{C_f-C_0}{t_f-t_0}

Whereas it is multiplied by the the inverse of the stoichiometric coefficient of NO₂ in the reaction that is 2. Moreover, the subscript <em>f</em> is referred to the final condition and the subscript <em>0</em> to the initial condition, thus, we obtain:

rate=\frac{1}{2}*\frac{0.00650M-0.0100M}{100s-0s}\\\\rate=-1.75x10^{-5}\frac{M}{s}

Clearly, it turns out negative since the concentration is diminishing due to its consumption.

Regards.

3 0
3 years ago
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