This question involves the concepts of the law of conservation of energy, kinetic energy, and potential energy.
The height of the hill is "166.76 m".
<h3>LAW OF CONSERVATION OF ENERGY:</h3>
According to the law of conservation of energy at the highest point of the roller coaster ride, that is, the hill, the whole (maximum) kinetic energy of the roller coaster is converted into its potential energy:
![Maximum\ Kinetic\ Energy\ Lost = Maximum\ Potential\ Energy\ Gain\\\\ \frac{1}{2}mv_{max}^2=mgh\\\\ h=\frac{v_{max}^2}{2g}](https://tex.z-dn.net/?f=Maximum%5C%20Kinetic%5C%20Energy%5C%20Lost%20%3D%20Maximum%5C%20Potential%5C%20Energy%5C%20Gain%5C%5C%5C%5C%0A%5Cfrac%7B1%7D%7B2%7Dmv_%7Bmax%7D%5E2%3Dmgh%5C%5C%5C%5C%0Ah%3D%5Cfrac%7Bv_%7Bmax%7D%5E2%7D%7B2g%7D)
where,
- h = height of the hill = ?
= maximum velocity = 57.2 m/s
- g = acceleration due to gravity = 9.81 m/s²
Therefore,
![h=\frac{(57.2\ m/s)^2}{2(9.81\ m/s^2)}\\\\ ](https://tex.z-dn.net/?f=h%3D%5Cfrac%7B%2857.2%5C%20m%2Fs%29%5E2%7D%7B2%289.81%5C%20m%2Fs%5E2%29%7D%5C%5C%5C%5C%0A)
<u>h = 166.76 m</u>
Learn more about the law of conservation of energy here:
brainly.com/question/101125
The smallest difference in voltage that can be resolved is referred to as the resolution. The resolution can be calculated with the following formula:
resolution=voltage range / digital range
The voltage range in our case is from -500mV to 500mV, which gives 1000mV.
The digital range on the other hand is 2^(number of bits).
It depends on what type of bit board we are using. If the ADC we are using is a 16 bit board, then 2^16=<span>65536.
So, the resolution is:
resolution=1000mV/</span><span>65536=0.015 mV</span>
A: decreases in specific heat capacity
Answer:
v₂=- 34 .85 m/s
v₁=0.14 m/s
Explanation:
Given that
m₁=70 kg ,u₁=0 m/s
m₂=0.15 kg ,u₂=35 m/s
Given that collision is elastic .We know that for elastic collision
Lets take their final speed is v₁ and v₂
From momentum conservation
m₁u₁+m₂u₂=m₁v₁+m₂v₂
70 x 0+ 0.15 x 35 = 70 x v₁ + 0.15 x v₂
70 x v₁ + 0.15 x v₂=5.25 --------1
v₂-v₁=u₁-u₂ ( e= 1)
v₂-v₁ = -35 --------2
By solving above equations
v₂=- 34 .85 m/s
v₁=0.14 m/s