Explain and define the angular momentum quantum number without the internet

Chemistry

1 answer:

brilliants [131]3 years ago

4 0

Answer:

The angular momentum quantum number, l, describes the shape of the orbital that an electron occupies. The lowest possible value of l is 0, and its highest possible value, depending on the principal quantum number, is n - 1.

You might be interested in

What is the mass of 8.90 moles of magnesium chloride, MgCl2?

Mazyrski [523]

(8.90/95.211) =0.09347 moles

3 0

3 years ago

True or False: Photosynthesis can happen anytime, regardless of the amount of reactants present or the presence of sunlight.

Arisa [49]

The answer is false .

3 0

3 years ago

Read 2 more answers

Molybdenum (Mo) has a body centered cubic unit cell. The density of Mo is 10.28 g/cm3. Determine (a) the edge length of the unit

ser-zykov [4K]

Answer:

For a: The edge length of the unit cell is 314 pm

For b: The radius of the molybdenum atom is 135.9 pm

Explanation:

For a:

To calculate the edge length for given density of metal, we use the equation:

$\rho=\frac{Z\times M}{N_{A}\times a^{3}}$

where,

$\rho$ = density = $10.28g/cm^3$

Z = number of atom in unit cell = 2 (BCC)

M = atomic mass of metal (molybdenum) = 95.94 g/mol

$N_{A}$ = Avogadro's number = $6.022\times 10^{23}$

a = edge length of unit cell =?

Putting values in above equation, we get:

$10.28=\frac{2\times 95.94}{6.022\times 10^{23}\times (a)^3}\\\\a^3=\frac{2\times 95.94}{6.022\times 10^{23}\times 10.28}=3.099\times 10^{-23}\\\\a=\sqrt[3]{3.099\times 10^{-23}}=3.14\times 10^{-8}cm=314pm$